这是我的剧本
- name: Host's luns
debug:
msg: "{{ luns }}"
vars:
luns: "{{ ansible_facts.lvm.pvs }}"
输出如下
TASK [Luns del vg] ************************************************************
ok: [awxworker_rhel6] => {
"msg": {
"/dev/sda2": {
"free_g": "20.72",
"size_g": "79.72",
"vg": "vg00"
},
"/dev/sdb1": {
"free_g": "3.99",
"size_g": "4.99",
"vg": "vg01"
},
"/dev/sdc1": {
"free_g": "0.99",
"size_g": "4.99",
"vg": "vg02"
},
"/dev/sdd1": {
"free_g": "4.99",
"size_g": "4.99",
"vg": "vg01"
}
}
}
我需要获取匹配的 vg 的 lun
Ej: "The vg01 luns are: /dev/sdb1 /dev/sdd1"
我已经尝试过其他方法
- name: Luns del VG
set_fact:
vg_luns: "{{ item }}"
with_items: "{{ ansible_facts.lvm.pvs }}"
vars:
VGname: "{{ VG }}"
when: ansible_facts.lvm.pvs.vg_luns.vg == VGname
- name: Print VG's luns
debug:
msg:
- "The {{ VGname }} luns are: {{ vg_luns }}"
VG 是一个外部变量,我将匹配的 VGname
$ ansible-playbook -i proyects/Inventory/awx_hosts -l testhost getvgluns.yml -e VG=vg01
希望你能帮助
Thanks in advance!
答案1
创建群组字典。例如
- set_fact:
vgs: "{{ vgs|d({})|
combine({item.0: item.1|
map(attribute='key')|
list}) }}"
loop: "{{ luns|dict2items|groupby('value.vg') }}"
给出
vgs:
vg00:
- /dev/sda2
vg01:
- /dev/sdb1
- /dev/sdd1
vg02:
- /dev/sdc1
那么选择就很简单了
- debug:
msg: "The {{ VG }} luns are: {{ vgs[VG]|join(' ') }}"
传达信息
shell> ansible-playbook playbook.yml -e VG=vg01
msg: 'The vg01 luns are: /dev/sdb1 /dev/sdd1'
答案2
无需 set_fact 或 Ansible 循环。将字典转换为列表并对其使用常规 Jinja 操作。
- debug:
msg: "The {{ VG }} luns are: {{ ansible_facts.lvm.pvs | dict2items | selectattr('value.vg', 'equalto', VG) | map(attribute='key') | join(' ') }}"