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如何在 shell 脚本中将多行字符串值分配给带有缩进的变量？

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如何在 shell 脚本中将多行字符串值分配给带有缩进的变量？

我想将以下多行字符串值分配给 shell 脚本中的变量，并具有精确的缩进和行。

Usage: ServiceAccountName LogFile
Where:
      ServiceAccountName - credentials being requested.
      LogFile            - Name of the log file

我一直在尝试遵循以下所有建议来做到这一点：如何在缩进的情况下将字符串值分配给多行变量？ 但没有结果。请建议。

REASON="$(cat <<-EOF
    Usage: ServiceAccountName LogFile
    Where:
      ServiceAccountName - credentials being requested.
      LogFile            - Name of the log file
EOF
)"
echo "$REASON"

这是我的脚本：

GetBatchCredentials.sh

if [ $# -ne 2 ]
then
   # RETURN INVALID USAGE
   GetBatchCredentials_Result="Error"
   GetBatchCredentials_Reason="$(cat <<-EOF
        Usage: ServiceAccountName LogFile
        Where:
          ServiceAccountName - credentials being requested.
          LogFile            - Name of the log file
    EOF
    )"
else
   //coding...
fi

该脚本是从以下脚本调用的：

. /www/..../scripts/GetBatchCredentials.sh arg1 arg2
if [ "$GetBatchCredentials_Result" != "Success" ]
then
   echo "Error obtaining FTP Credentials"
   echo "$GetBatchCredentials_Reason"
   ret=1
else
   echo "Obtained Credentials"
fi

答案1

与其在此处文档中添加一只无用的猫，不如

REASON="\
Usage: ServiceAccountName LogFile
Where:
      ServiceAccountName - credentials being requested.
      LogFile            - Name of the log file"

或者

REASON="$(printf '%s\n' \
    "Usage: ServiceAccountName LogFile" \
    "Where:" \
    "      ServiceAccountName - credentials being requested." \
    "      LogFile            - Name of the log file")"

答案2

你的剧本对我有用。我所做的只是在顶部添加 #!/bin/sh 。然后使其可执行并运行它。您还可以使用 sh 和原始脚本的名称。

#!/bin/sh
REASON="$(cat <<-EOF
Usage: ServiceAccountName LogFile
Where:
      ServiceAccountName - credentials being requested.
      LogFile            - Name of the log file
EOF
)"
echo "$REASON"

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