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Bash 调用 PHP，等待 PHP 进程完成？

tag-icon • tag-icon bash shell-script php
Bash 调用 PHP，等待 PHP 进程完成？

这是我的 bash 脚本

#!/bin/bash
timestamp() {
  date +"%T"
}
pushd 'httpdocs/DIR1/DIR2'; 
file="Lock3.key"
if [ -f "$file" ]
then
    echo "$file found, Session is already in progress" $(date)
else
    echo "$file was not found, Its safe to start the script"  $(date)
    echo "Running Ebay Stock Only Script" $(date)
#Its possible to double check if the script is running by checking memory.
#ps aux | grep "php Cron-Run.php" (Not safe)
php Cron-Run.php > Output.log
echo "Finished Running Script, Lock file is deleted by PHP, Now exiting" $(date)
fi
exit

这是从 cron 作业运行的，并且有效。但我想要的是最后一个echo仅在 PHP 进程完成时运行（它将运行一个小时），并且当电子邮件通过时，很高兴看到最后一个的输出echo以及相关时间。

目前，echoPHP 脚本调用后两秒运行。

答案1

我可以使用等待函数暂停/等待该过程完成。

工作部分的示例：

#!/bin/bash
timestamp() {
  date +"%T"
}
pushd 'httpdocs/DIR1/DIR2'; 
file="Lock3.key"
if [ -f "$file" ]
then
    echo "$file found, Session is already in progress" $(date)
else
    echo "$file was not found, Its safe to start the script"  $(date)
    echo "Running Ebay Stock Only Script" $(date)
#Its possible to double check if the script is running by checking memory.
#ps aux | grep "php Cron-Run.php" (Not safe)
php Cron-Run.php > Output.log
wait
echo "Finished Running Script, Lock file is deleted by PHP, Now exiting" $(date)
fi
exit

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