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有没有办法告诉 wvdial 等待命令的答复？

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有没有办法告诉 wvdial 等待命令的答复？

某些AT命令会wvdial延迟返回答案。这段时间取决于命令。例如，当您想要扫描可用网络时，可以使用该AT+COPS=?命令。扫描过程大约需要30s，但wvdial不会等到完成后重新发送命令。第二次尝试后，wvdial放弃并出现以下错误：

# wvdial info-scan
--> WvDial: Internet dialer version 1.61
--> Initializing modem.
--> Sending: AT+COPS=?
--> Re-Sending: AT+COPS=?
--> Modem not responding.

一段时间（30秒）后，我可以通过发出另一个命令wvdial，它可以是任何命令，例如ATZ+CFUN=1，当调制解调器已经打开时，它不执行任何操作，但发送命令后，我得到前一个命令的输出：

# wvdial modem-start
--> WvDial: Internet dialer version 1.61
--> Initializing modem.
--> Sending: ATZ+CFUN=1
+COPS: (2,"T-Mobile.pl","TM PL","26002",2),(1,"T-Mobile.pl","TM
PL","26002",7),(3,"Plus","PLUS","26001",7),
(3,"Play","Play","26006",7),(3,"Orange","Orange","26003",7),
(3,"Play","Play","26006",2),(3,"Orange","Orange","26003",2),
(3,"Plus","PLUS","26001",2),,(0,1,2,3,4),(0,1,2)
OK

那么有没有办法为命令设置某种超时，以便他们可以获得延迟的答案？

答案1

我通过创建这个 python 脚本的一些技巧解决了这个问题，它将等待大约 40 秒或一分钟：

import serial
import subprocess
import time

ser = serial.Serial('/dev/modem0', 460800, timeout=2)

cmd = 'AT+COPS=0\r\n'
ser.write(cmd)
ser.sendBreak()

s = []
time_now = time.time()
while(time.time()-time_now)<=40:
    newdata = ser.read()
    if newdata is not None or newdata!="":
            global s
            s.append(newdata)
ser.close
print "".join(s)

subprocess.Popen(["wvdial"])

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