从文件中删除特殊字符

Question

我已经这样了：

'< Jan 20 Sep> This is the sample out put  
This is Sample 
>

'< Jan 21 Sep> This is the sample out put 
This is Known Errors 
 > 

所以我需要从文件中删除所有 > 特殊字符。仅需要删除存在一个特殊字符 > 的行。我想要下面的输出

'< Jan 20 Sep> This is the sample out put 
This is Sample 
'< Jan 21 Sep> This is the sample out put  
This is Known Errors 

Answer 1

如果“>”字符出现在问题中所示的单行中，您可以：

grep -wv '>' thefile

结果：

'< Jan 20 Sep> This is the sample out put
This is Sample

'< Jan 21 Sep> This is the sample out put
This is Known Errors

Answer 2

这将删除>每行开头的字符并将输出打印到 STDOUT。如果要将输出写入文件，则需要使用-i选项或重定向输出。sed

sed 's%^>%%' <filename>

例如，您可以使用此命令进行测试

% sed 's%^>%%' <<'EOF'
'< Jan 20 Sep> This is the sample out put
This is Sample
>
EOF

结果

'< Jan 20 Sep> This is the sample out put
This is Sample

Answer 3

这些命令应该可以完成您正在寻找的内容。

command | sed '/^ \?> \?$\|^$/d'

或者

sed '/^ \?> \?$\|^$/d' file.txt

正则表达式读起来像这样。

任何匹配的东西/pattern/

>包含且带有可选的前置或尾随空格的行^ \?> \?$

或者\|

为空^$

删除它d