作为服务 Ubuntu 运行 python 脚本返回退出代码 =1

Question

我创建一个文件 job_tracking.py

#!/home/thao/venv/bin/python
while True:
    print("hello")
    # job_tracking_stats()
    log_app('Stats tracking Sleeping...')
    time.sleep(5)
    log_app('Stats tracking Wakeup...')

以及 job_tracking.service

[Unit]
Description=Test Service
After=multi-user.target
[email protected]

[Service]
Type=simple
User=thao
ExecStart=/home/thao/venv/bin/python /home/thao/vodjs/job_tracking.py
StandardInput=tty-force

[Install]
WantedBy=multi-user.target

我按照这个教程https://websofttechs.com/tutorials/how-to-setup-python-script-autorun-in-ubuntu-18-04/

但是当我检查我的状态服务时它返回

Thg 12 15 11:42:50 thao-HP-ZBook-15 systemd[1]: Started Test Service.
Thg 12 15 11:42:50 thao-HP-ZBook-15 systemd[1]: job_tracking.service: Main process exited, code=exited, status=1/FAILURE
Thg 12 15 11:42:50 thao-HP-ZBook-15 systemd[1]: job_tracking.service: Failed with result 'exit-code'.

我做错了什么？编辑：/home/thao/logs我在终端中运行时需要一个文件夹，但我不知道在 systemd 中运行时需要哪个文件夹。这是 log_app 函数：

import logging
from logging.handlers import RotatingFileHandler

log_formatter = logging.Formatter('%(asctime)s: %(message)s', datefmt='%Y-%m-%d %H:%M:%S')

logFile = './logs/app.log'
log_handler = logging.handlers.TimedRotatingFileHandler(logFile, when="D", interval=1, backupCount=0)
log_handler.setFormatter(log_formatter)
log_handler.setLevel(logging.INFO)

app_log = logging.getLogger('P2P')
app_log.setLevel(logging.INFO)
app_log.addHandler(log_handler)



def log_app(string):
    #In ra bien string trong file log duoi LEVEL INFO
    app_log.info(string)
    print(string)