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如何使某个函数“超时”，使其每 5 秒仅运行一次，尽管每秒调用多次

tag-icon • tag-icon command-line bash scripts notification sed
如何使某个函数“超时”，使其每 5 秒仅运行一次，尽管每秒调用多次

见下文：

still_notify=false
has_been_notified=false
notify()
{
        $has_been_notified && return
        watching=$(if [[ $(GET http://$ipplexserver:32400/status/sessions?X-Plex-Token=$plexapitoken | grep -o "^</Video>$") ]]; then echo true; else echo false; fi)
        if [[ $watching = false ]]
        then
                clear
                echo "Updating notification"
                echo "--------------------------------"
                echo "Nobody is watching media on your plex server anymore"
                echo "You can now update plex"
                echo "-----"
                echo "You see this message because you chose to be notified when you were trying to update plex"
                echo "--------------------------------"
                sed -i "s|^still_notify=true$|still_notify=false|" $filelocation/advancedplexapi.sh
                read -rp "continue | update: " notifyoption
                if [[ ${notifyoption,,} = "continue" ]]
                then
                        echo "this is to exit out of the if statement" >> /dev/null

                elif [[ ${notifyoption,,} = update ]]
                then
                        option=update
                fi
                has_been_notified=true
        fi
}

if [[ $still_notify = true ]]
then
        trap notify DEBUG
fi

if [[ if-statement ]]
then
       sed -i "s|^still_notify=false$|still_notify=true|" $filelocation/advancedplexapi.sh
       trap notify DEBUG
fi

这是我的脚本中的通知系统。当运行底部的 if 语句时，脚本将继续运行，但在后台，它会检查 plex api，如果 if 语句为真，它会显示一条消息。每次在脚本中执行命令时，它都会检查 api（查看监视变量）（因为 trap 命令中使用了 DEBUG）。我的脚本非常大（2800 行），以至于它每秒运行多次通知函数（有时每秒 10 次）。这使我的脚本非常慢（由于 api 请求的数量），有时甚至无法使用，而该函数甚至不必运行那么多次。

我希望一旦该函数运行，接下来的 5 秒内它就无法运行，无论 trap 命令调用它多少次。就像函数的睡眠/超时一样。我尝试了以下方法，但没有奏效：

timeout=false
still_notify=false
has_been_notified=false
notify()
{
        if [[ $timeout = false ]]
        then
        sed -i "s|^timeout=false$|timeout=true|" $filelocation/advancedplexapi.sh
        $has_been_notified && return
        watching=$(if [[ $(GET http://$ipplexserver:32400/status/sessions?X-Plex-Token=$plexapitoken | grep -o "^</Video>$") ]]; then echo true; else echo false; fi)
        if [[ $watching = false ]]
        then
                clear
                echo "Updating notification"
                echo "--------------------------------"
                echo "Nobody is watching media on your plex server anymore"
                echo "You can now update plex"
                echo "-----"
                echo "You see this message because you chose to be notified when you were trying to update plex"
                echo "--------------------------------"
                sed -i "s|^still_notify=true$|still_notify=false|" $filelocation/advancedplexapi.sh
                read -rp "continue | update: " notifyoption
                if [[ ${notifyoption,,} = "continue" ]]
                then
                        echo "this is to exit out of the if statement" >> /dev/null

                elif [[ ${notifyoption,,} = update ]]
                then
                        option=update
                fi
                has_been_notified=true
        fi
}

while true
do
        sleep 5s
        sed -i "s|^timeout=true$|timeout=false|" $filelocation/advancedplexapi.sh
done &

if [[ $still_notify = true ]]
then
        trap notify DEBUG
fi

if [[ if-statement ]]
then
       sed -i "s|^still_notify=false$|still_notify=true|" $filelocation/advancedplexapi.sh
       trap notify DEBUG
fi

答案1

您可以创建一个中间函数来跟踪时间。如果 rlimit 超过一秒，则将 epoch 重新设置为全局范围内的 rlimit 变量。

#!/bin/bash

debug_func(){
    local -n a=rlimit
    ((($EPOCHSECONDS - a) > 1)) && \
        { a=$EPOCHSECONDS; notify; }
}
trap debug_func DEBUG

notify(){
    echo "Ding Dong!"
}

echo  1..
echo  2..
echo  3..
sleep 2
echo  4..

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