在匹配的部分之间引入空行

Question

我有以下 bash 函数，用于提取在和sed之间出现的部分，其中是注释字符。最后，我删除了注释字符和所有空格。## Mode: org## # End of org#

这是我的意见

cat /home/flora/docs/recnotes.txt
   ## Mode: org
   #  Assigns shell positional parameters or changes the values of shell
   #  options.  The -- option assigns the positional parameters to the
   #  arguments of {set}, even when some of them start with an option
   #  prefix `-'.
   ## # End of org

     ;; Mode: org
     ;  Assigns shell positional parameters or changes the values of shell
     ;  options.  The -- option assigns the positional parameters to the
     ;  arguments of {set}, even when some of them start with an option
     ;  prefix `-'.
     ;; # End of org
 
       @c Mode: org
       @c  Assigns shell positional parameters or changes the values of shell
       @c  options.  The -- option assigns the positional parameters to the
       @c  arguments of {set}, even when some of them start with an option
       @c  prefix `-'.
       @c # End of org

这是 中的实现的 bash 函数sed。

capture ()
{
 local efile="$1"

 local charcl begorg endorg

 charcl_ere='^[[:space:]]*([#;!]+|@c|\/\/)[[:space:]]*'
 charcl_bre='^[[:space:]]*\([#;!]\+\|@c\|\/\/\)[[:space:]]*'

 begorg="${charcl_bre}"'Mode: org$'
 endorg="${charcl_bre}"'# End of org$'

 mdr='^Mode: org$' ; edr='^# End of org$'

 sed -n "/$begorg/,/$endorg/ s/$charcl_bre//p" "$efile" |
  sed "/$mdr\|$edr/d"
}

最初，我有两个命令

begorg='${charcl_bre}Mode: org$'
endorg='${charcl_bre}# End of org$'

没有扩大变量charcl_bre。

输出为

Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.
Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.
Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.

我想要做的是在各部分之间留一行空白。

Answer 1

根据您的最新编辑，您只需要在不同的注释部分之间留一个空行即可。您可以通过将最后一个sed命令从以下内容更改为以下内容：

sed "/$mdr\|$edr/d"

到：

sed "/$mdr/d; s/$edr//"

这会将sed命令从删除$mdr和$edr行更改为仅删除$mdr行并$edr用空字符串替换该行，从而有效地保留所需的空白行。

输出为：

Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.

Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.

Assigns shell positional parameters or changes the values of shell
options.  The -- option assigns the positional parameters to the
arguments of {set}, even when some of them start with an option
prefix `-'.