我是使用 python-quickly 开发应用程序的新手。这是我正在尝试的示例代码。每次我运行它时,都会根据 login.php 播放视频。但启动需要时间,或者我的理解是会发生缓冲。有没有办法让 URL 仅在第一次缓冲,然后每次播放时都无需缓冲?
import gettext
from gettext import gettext as _
gettext.textdomain('smallbrowser')
from gi.repository import Gtk, WebKit # pylint: disable=E0611
import logging
logger = logging.getLogger('smallbrowser')
from smallbrowser_lib import Window
from smallbrowser.AboutSmallbrowserDialog import AboutSmallbrowserDialog
from smallbrowser.PreferencesSmallbrowserDialog import PreferencesSmallbrowserDialog
# See smallbrowser_lib.Window.py for more details about how this class works
class SmallbrowserWindow(Window):
__gtype_name__ = "SmallbrowserWindow"
def finish_initializing(self, builder): # pylint: disable=E1002
"""Set up the main window"""
super(SmallbrowserWindow, self).finish_initializing(builder)
self.AboutDialog = AboutSmallbrowserDialog
self.PreferencesDialog = PreferencesSmallbrowserDialog
# Code for other initialization actions should be added here.
self.refreshbutton = self.builder.get_object("refreshbutton")
self.urlentry = self.builder.get_object("urlentry")
self.scrollwindow = self.builder.get_object("scrollwindow")
self.webview = WebKit.WebView()
self.scrollwindow.add(self.webview)
self.webview.show()
self.webview.open("login.php")
def on_refreshbutton_clicked(self, widget):
print "refresh"