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bash 字符串比较

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bash 字符串比较

我想将输出与字符串进行比较。我的脚本如下所示：

#!/bin/bash
DRBD=$(drbd-overview)
COMP=' 0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate'

DEBUG=1

if [ $DEBUG == "1" ];
then
  echo "Debug:"
  echo $COMP
  echo $DRBD
  echo "Debug-Ende"
fi

if [[ "x$DRBD" = "x$COMP" ]];
then
  RTRN='Check_OK'
else
  RTRN="$DRBD"
fi

echo "Return: $RTRN"

& bash -x script.sh 看起来像这样：

bash -x scripts.sh
++ drbd-overview
+ DRBD=' 0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate '
+ COMP=' 0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate'
+ DEBUG=1
+ '[' 1 == 1 ']'
+ echo Debug:
Debug:
+ echo 0:nfs-ha/0 Connected Secondary/Primary UpToDate/UpToDate
0:nfs-ha/0 Connected Secondary/Primary UpToDate/UpToDate
+ echo 0:nfs-ha/0 Connected Secondary/Primary UpToDate/UpToDate
0:nfs-ha/0 Connected Secondary/Primary UpToDate/UpToDate
+ echo Debug-Ende
Debug-Ende
+ [[ x 0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate  = \x\ \0\:\n\f\s\-\h\a\/\0\ \ \C\o\n\n\e\c\t\e\d\ \S\e\c\o\n\d\a\r\y\/\P\r\i\m\a\r\y\ \U\p\T\o\D\a\t\e\/\U\p\T\o\D\a\t\e ]]
+ RTRN=' 0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate '
+ echo 'Return:  0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate '
Return:  0:nfs-ha/0  Connected Secondary/Primary UpToDate/UpToDate

我做错了什么 $COMP 在 bash 语句中被转义？

答案1

两个字符串不相同。$DRBD末尾有一个空格，而$COMP没有（您可以在跟踪输出中看到这一点）。这就是比较未设置RTRN为 的原因Check_OK。

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