/bin/sh：导入“模块”的函数定义时出错

Question

我现在有脚本，但它总是提示这是错误。

stderr=/bin/sh: module: line 1: syntax error: unexpected end of file /bin/sh: error importing function definition for模块'`

#!/bin/sh
#
# pgp.sh
# Script to take PGP Command Line 6.5.8 (Freeware) output from PGPPackageService
# or PGPUnpackageService and execute the appropriate GnuPG commands 
#
if [ "$9" = "-se" ]
then MODE="encrypt_and_sign"
fi
if [ "$9" = "-e" ]
then MODE="encrypt_only"
fi
if [ "$8" = "-o" ]
then MODE="decrypt"
fi
#
case "$MODE" in
    "encrypt_and_sign")
        #
        # Logic for encrypt and sign
        #
        if [ "$6" = "+armor=on" ];
            then
                OPTIONS='--armor '$OPTIONS
        fi
        if [ "$7" = "+textmode=on" ];
            then
                OPTIONS='--textmode '$OPTIONS
        fi
        PASS=${15}
        OUTFILE=${17}
        USER=${13}
        REMOTE=${11}
        INFILE=${10}
        #Original script from Bryce
        #echo "$PASS" | "gpg $OPTIONS --no-tty --output $OUTFILE --passphrase-fd 0 -u $USER -r $REMOTE --sign --encrypt $INFILE"
        #script from Tyn, removed --passphrase-fd 0 and echo and double quotes
        #03252015: Tyn: Added --trust-model always for newly imported keys to be usable
        /usr/bin/gpg --trust-model always $OPTIONS --no-tty --output $OUTFILE -u $USER -r $REMOTE --sign --encrypt $INFILE

    ;;
    "encrypt_only")
        #
        # Logic for encrypt
        #
        if [ "$6" = "+armor=on" ];
            then
                OPTIONS='--armor '$OPTIONS
        fi
        if [ "$7" = "+textmode=on" ];
            then
                OPTIONS='--textmode '$OPTIONS
        fi
        OUTFILE=${13}
        REMOTE=${11}
        INFILE=${10}
        #original script from Bryce
        #echo "$PASS" | "gpg $OPTIONS --no-tty --output $OUTFILE --passphrase-fd 0 -r $REMOTE --encrypt $INFILE"
        #script from Tyn, removed --passphrase-fd 0 and echo and double quotes
        #03252015: Tyn: Added --trust-model always for newly imported keys to be usable
        /usr/bin/gpg --trust-model always $OPTIONS --no-tty --output $OUTFILE -r $REMOTE --encrypt $INFILE
    ;;
    "decrypt")
        #
        # Logic for decrypt
        #
        PASS=${7}
        OUTFILE=${9}
        INFILE=${5}
        #Original script from Bryce
        #echo "$PASS" | "gpg --no-tty --output $OUTFILE --passphrase-fd 0 --decrypt $INFILE"
        #script from Tyn, removed --passphrase-fd 0 and echo and double quotes
        #03252015: Tyn: Added --trust-model always for newly imported keys to be usable
        /usr/bin/gpg --trust-model always --no-tty --output $OUTFILE --decrypt $INFILE
    ;;
esac

Answer 1

看起来您的环境中有一个损坏的导出函数，如下所示（该函数缺少分号和右大括号）：

$ env "BASH_FUNC_foo%%"="() {  echo foo" bash -c "echo blah"
bash: foo: line 1: syntax error: unexpected end of file
bash: error importing function definition for `foo'
blah

Bash 通过环境导出函数并自动从那里读取它们，当然如果它们有语法错误就会抱怨。即使开始时它也会这样做sh。这意味着您在运行任何脚本时都会遇到相同的错误，例如这个简单的错误：

#!/bin/sh
echo hello

您可以使用类似的内容检查环境中的内容env | grep module（前缀BASH_FUNC_和后缀%%可能不同）。然后，您需要找出该环境变量的设置位置。不过，在 Bash 脚本中设置它相当困难，因为%不是 shell 变量名称中的有效字符。