Bash If 语句帮助

Question

我有这个 if 语句：

if $type = 1 then
 date +%s | md5 | base 64 | head -c $length >> $name.txt
        elseif $type = 2 then
        date +%s | shasum | base 64 | head -c $length >> $name.txt
                elseif $type = 3 then
                openssl rand -base64 $length  >> $name.txt
fi

我一直收到错误：

./password: line 32: syntax error near unexpected token `fi'
./password: line 32: `fi'

可能我做了一些愚蠢的事情但我不知道我错在哪里！

提前致谢！！

Answer 1

始终组织你的代码，并在执行整数条件时使用 -eq

if [ $type -eq 1 ]
        then 
     date +%s | md5 | base 64 | head -c $length >> $name.txt 

   elif [ $type -eq 2 ]
       then 
           date +%s | shasum | base 64 | head -c $length >> $name.txt 

   elif [ $type -eq 3 ]
     then 
         openssl rand -base64 $length >> $name.txt 

fi