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获取特殊字符模式之间的线条

tag-icon • tag-icon command-line text-processing awk
获取特殊字符模式之间的线条

以下是我的输入文件：

---
{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}
---

#Hello

---
This is sample
---

```
var x=1;
entry.forEach(function(item){
    x=x++;
})
```

我期望的输出是第一的2'---‘

{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}

我该如何实现它？使用awk，我只能通过替换'来实现这一点---' 包含一些字符串，例如 'start'/'end'。

awk '/start/{f=1;next} /end/{f=0;exit} f'  $FILE_PATH

答案1

这是一个解决方案：

awk '/^---/ {mark++; next} mark == 1 {print}' $FILE_PATH

其结果为：

{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}

mark每次遇到行时，都会增加名为的变量---。我们只在 时打印行mark == 1。这是一个很好的解决方案，因为它可以让你提取任意块---。也就是说，如果我们想要第二一大块---分隔的文本，我们可以运行：

awk '/^---/ {mark++; next} mark == 2 {print}' $FILE_PATH

这给了我们：


#Hello

答案2

这是一个选项，举个例子：

sed -n '/^{$/,/^}$/p' file

输出：

{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}

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