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如何为列出的文件夹创建 bash 菜单

tag-icon • tag-icon command-line bash scripts backup
如何为列出的文件夹创建 bash 菜单

我在 ubuntu 中创建了一个简单的 bash 脚本来备份我的项目：

#!/bin/bash

save_backup_path=~/Downloads/my_backup
web_projects_path=~/Downloads/my_backup/projects

cd $web_projects_path || return

for f in *; do
    if [ -d "$f" ]; then
        echo "backup project $f";
        tar -zcf $save_backup_path/"$f"-$(date +%d-%m-%Y).tar.gz --exclude="$f"/node_modules --exclude="$f"/vendor --exclude="$f"/storage/framework/views/*.php --exclude="$f"/public/uploaded "$f"
    fi
done

它将为每个文件夹（项目名称）创建一个 tar.gz。

我想要创建一个菜单并选择我想要创建备份的项目例如:(1、2、3......或*代表全部)

我不知道如何处理选择并完成工作

我用它来存储所有项目名称（文件夹名称）

for f in *; do
  if [ -d "$f" ]; then
    readarray -t project_names < <(echo "$f")
  fi
done

但在列出选择时

echo "Select project for backup:"
select choice in "${project_names[@]}"; do
  [[ -n $choice ]] || { echo "Invalid choice. Please try again." >&2; continue; }
  break
done

它只显示最后一个（最后一个文件夹名称）。

我怎样才能列出所有项目并为选定的一个或全部创建 tar.gz（如果选定的是 *）

***更新****

#!/bin/bash

### backup the projects

save_backup_path=~/Downloads/my_backup
web_projects_path=~/Downloads/my_backup/projects

cd $web_projects_path || return

declare -a project_names
i=1
for d in */
do
    project_names[i++]="${d%/}"
done

echo "Select project for backup:"
select choice in "${project_names[@]}"; do
  [[ -n $choice ]] || { echo "Invalid choice. Please try again." >&2; continue; }
  break
done

echo "backup project $choice ..."
tar -zcf $save_backup_path/"$choice"-$(date +%d-%m-%Y).tar.gz --exclude="$choice"/node_modules --exclude="$choice"/vendor --exclude="$choice"/storage/framework/views/*.php --exclude="$choice"/public/uploaded "$choice"

我已经创建了带选项的选定，现在它仅适用于选定的项目。我该如何处理所有项目？如果用户选择 * 以将它们全部（单独）

答案1

我知道如何备份所有项目。将 * 添加到现有数组

最终版本如下：

#!/bin/bash

save_backup_path=~/Downloads/my_backup
web_projects_path=~/Downloads/my_backup/projects

cd $web_projects_path || return

declare -a project_names
i=1
for d in */
do
    project_names[i++]="${d%/}"
done
project_names[i++]="*"

echo "Select project for backup:"
select choice in "${project_names[@]}"; do
  [[ -n $choice ]] || { echo "Invalid choice. Please try again." >&2; continue; }
  break
done

backup_project() {
  echo "backup project $1 ..."
  tar -zcf $save_backup_path/"$1"-$(date +%d-%m-%Y).tar.gz --exclude="$1"/node_modules --exclude="$1"/vendor --exclude="$1"/storage/framework/views/*.php --exclude="$1"/public/uploaded "$1"
}

if [ "$choice" == "*" ]; then
    unset project_names[-1]
    for project in "${project_names[@]}"; do
      backup_project "$project"
    done
  else
    backup_project "$choice"
fi

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