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Bash 脚本：用户输入（读取）无法正常工作

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Bash 脚本：用户输入（读取）无法正常工作

我正在编写一个 BASH 脚本，该脚本应该根据文件的名称、内容删除文件或直接关闭程序。具体来说，我在根据文件内容删除文件时遇到问题（情况 2）。我可以使用与内容匹配的任何文件填充文件。但是，当用户应该输入是否要删除文件（使用读取）时，我的代码出现故障。该变量不会要求用户输入，而是自动填充要删除的文件的位置。

#!/bin/bash

#set -x
#Programmer: Redacted
#Z: ID: Redacted
#Assignment:  cleaner.sh

directory=`pwd` #sets the directory variable to pwd
string="string"
file="file"
fileFound=matched.txt
possibleFiles=''
result=''
function askDelete #asks for verification
{
    #echo "$fileName was found, still want to delete it? (y/n)"
    read -p "$fileName was found, still want to delete it? (y/n)" continue
    echo "Continue is equal to: $continue"
}


echo    "Welcome to my CLEANER script!"
echo    "Enter 1: delete by filename."
echo    "Enter 2: delete by a string within the file."
echo    "Enter 3 or quit: exit this program."
read command
    case $command in
    "file")
        command=1 ;;
    "string")
        command=2 ;;
    esac

case $command in
    1)
            #Prompts user for which file they want to delete
        echo "What file would you like to delete? "
        read fileName
        #find $PWD -type f -name "$fileName"
        #result= -x $fileName
        if [ -a "$fileName" ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                        echo "File has been removed"
                    else
                        echo "File has not been removed"
                fi

            else
                echo "No files were found"
        fi

    ;;

    #case where user entered 2
    #user wants to enter a string within the files to delete
    2)
        touch 'matched.txt' #creates the file that will be used
        echo "Enter the string that you wish to have the files containing it to be destroyed"
        read pattern    #user enters what they want to search for
        find $PWD -type f 1>possibleFiles.txt
        #echo $PWD
        #grep -q "$pattern" 'foundFile.txt' 1> matched.txt
        echo 'This is where it breaks'
        cat possibleFiles.txt | while read fileName
        do
            #\echo $fileName
            grep -q "$pattern" "$fileName" 1> matched.txt
            if [ $? == 0 ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                    else
                        echo  "No found files have been removed"
                fi
            else
                echo "No matches for the pattern were found"
            fi
        done
#
#       if [ $? == 0 ]
#           then
#               askDelete
#               if [ $continue == "Y" ] || [ $continue == "y" ]
#                   then
#                       #cat matched.txt 
#                       for file in 'matched.txt'
#                       do
    #                       echo 'bleh'
#                       done
    #               else
#                       echo  "No found files have been removed"
#               fi
#           else
#               echo "No matches for the pattern were found"
#       fi
#       fi
        ;;

    #case where user entered 3
    #user wants to exit
    3)
        echo "Goodbye friend"
        exit
    ;;

    *)
        echo Digit 1, 2 or 3 must be entered
esac

我相信问题出在程序顶部附近的askDelete函数内部的某个地方。具体来说，是这一行： read -p "$fileName was found, still Want to delete it? (y/n)" continue

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答案1

因为整个块while...done已从stdin文件重定向（然后间接通过管道）possibleFiles.txt，因此该块内的每个命令都继承相同的stdin.因此，虽然这就是您想要的，read但实际上并不是您想要的，因为它正在消耗所使用的askDelete同一行输入。possibleFiles.txtread

幸运的是，tty（您的终端）仍然可以通过/dev/tty.只需将循环内部替换askDelete为askDelete </dev/tty，一切就应该按预期工作。

您仍然应该添加更多验证：例如，这个程序无法在终端之外运行（用其他文件提供预填充的 y/n 答案），因为这个简单的更正/dev/tty将不再起作用：您必须找到方法不这样做“覆盖” stdin。

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