如何将 a 添加*
到此 bash 脚本创建的框的中间?
#!/bin/bash
#
# raami joonistamine
echo -n "sisesta ridade arv: "
read rida
echo -n "sisesta tärnide arv: "
read tarn
# genereeri rea numbrid
for ((i = 1; i <= $rida;i++))
do
echo -n "$i "
# kui on esimene või viimane rida
if [ $i -eq 1 -o $i -eq $rida ]; then
# tärnidest tulev rida
for((j = 1; j <=$tarn; j++))
do
echo -n "* "
done
# teised read
else
echo -n "* "
# tühikud
for((j = 2; j < $tarn;j++))
do
echo -n " "
done
echo -n "* "
fi
echo
done
答案1
改变你的最内层循环:
# tühikud
for((j = 2; j < $tarn;j++))
do
echo -n " "
done
到
# tühikud
for((j = 2; j < $tarn;j++))
do
if [ "$i" -eq "$(( (rida+1) / 2 ))" ] && [ "$j" -eq "$(( (tarn+1) / 2 ))" ]; then
echo -n '* '
else
echo -n " "
fi
done
也就是说,当您检测到要输出最中间的字符时,插入 a*
而不是空格。
对于行中稍微更精确的位置:
# tühikud
for((j = 2; j < $tarn;j++))
do
if [ "$i" -eq "$(( (rida+1) / 2 ))" ] && [ "$j" -eq "$(( (tarn+1) / 2 ))" ]; then
if [ "$(( tarn%2 ))" -eq 0 ]; then
echo -n ' *'
else
echo -n '* '
fi
else
echo -n " "
fi
done
不要输出单个字符,而是一次输出整行。这样效率更高,并且您只需要关心三种类型的行:顶部/底部行、中间行和其他行:
#!/bin/bash
read -r -p 'Height: ' rows
read -r -p 'Width : ' cols
topbottom=$( yes '*' | head -n "$cols" | tr '\n' ' ' )
printf -v midrow '*%*s*%*s*' "$(( cols - 2 ))" "" "$(( cols - 2 ))" ""
printf -v otherrows '*%*s*' "$(( 2*(cols - 2) + 1 ))" ""
for (( row = 0; row < rows; ++row )); do
if (( row == 0 )) || (( row == rows - 1 )); then
thisrow=$topbottom
elif (( row == rows / 2 )); then
thisrow=$midrow
else
thisrow=$otherrows
fi
printf '%2d %s\n' "$(( ++n ))" "$thisrow"
done