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bash 函数中正确的引号转义/保留

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bash 函数中正确的引号转义/保留

如果我在终端中输入以下带有 2 个参数的命令，则可以满足我的需要：

mycommand 'string that includes many spaces and double quotes' 'another string that includes many spaces and double quotes'

现在我将上面的内容移至 bash 脚本中。

C=mycommand 'string that includes many spaces and double quotes'
function f {
 $C $1
}
# let's call it
f 'another string that includes many spaces and double quotes'

显然，这不会产生相同的结果，或任何有用的结果。但我无法想出保留和/或正确转义引号、空格以及保留实际参数数量的正确方法我的命令视为 2。

我在 Mac 上使用 GNU bash 版本 3.2.57。

答案1

如果您引用每个参数，它将作为位置参数正确处理：

#!/usr/local/bin/bash
f() {
  echo "function was called with $# parameters:"
  while ! [[ -z $1 ]]; do
    echo "  '$1'"
    shift
  done
}
f "param 1" "param 2" "a third parameter"
$ ./459461.sh
function was called with 3 parameters:
  'param 1'
  'param 2'
  'a third parameter'

但请注意，包含（即最外面的）引号是不是参数本身的一部分。让我们尝试稍微不同的函数调用：

$ tail -n1 459461.sh
f "them's fightin' words" '"Holy moly," I shouted.'
$ ./459461.sh
function was called with 2 parameters:
  'them's fightin' words'
  '"Holy moly," I shouted.'

请注意，'输出中复制的参数周围的 s 来自echo函数中的语句，而不是参数本身。

为了使您的示例代码更加具有引号意识，我们可以这样做：

C=mycommand
f() {
  $C "unchanging first parameter" "$1"
}
# let's call it
f 'another string that includes many spaces and double quotes'

或这个：

C=mycommand
f() {
  $C "$1" "$2"
}
# let's call it
f 'Some string with "quotes" that are scary' 'some other "long" string'

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