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正则表达式 - 捕获时间戳后的字符串

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正则表达式 - 捕获时间戳后的字符串

寻找一个有效的正则表达式来捕获以下时间戳后面的字符串：

<38>Oct 10 14:32:29 UAT01 
<86>Oct 10 14:32:29 Test04 
<13>Oct 10 14:35:09 Dev02
<13>Oct 10 14:35:10 Test03

答案1

鉴于问题是专门要求正则表达式：

grep -Eo '\s(\w+).$' file

 UAT01 
 Test04 
 Dev02
 Test0

解释：

`\s` matches any whitespace character.
`(\w+)` is the first Capturing Group 
 `\w+` matches any word character  and it is equal to [a-zA-Z0-9_]
 `+ ` Quantifier — Matches between one and unlimited times, as many times as possible.
 `.` matches any character (except for line terminators)
 `$` asserts position at the end of the string, or before the line terminator right at the end of the string.

cut使用或可以更轻松地提取最后一个字符串awk

cut -d' ' -f 7 file

awk '{print $7}' file

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