我有一个文件(超过 1000 行),需要以某种格式获取输出。我需要看看每个人有多少行thr
。在下面的情况下,我有 3 thr
s,5、4、2 分别是每行的计数thr
。
输入:
19608250477[thr=22321]: Res90 at
1: 0x00007f1fb38d5089
2: 0x00007f1fb5565c79
3: 0x00007f1fbb097775
4: 0x00007f1fbb034a69
5: 0x00007f1fbb035467
19601889333[thr=19068]: Res87 at
1: 0x00007f1fc15f86c0
2: 0x00007f1fc1a27d7c
3: 0x00007f1fc1d0f312
4: 0x00007f1fc1caf054
16236545786[thr=55528]: Res67 at
1: 0x00007f1fb4959a90
2: 0x00007f1fb557ad94
我需要如下的输出
thr=22321 ; Count 5 # Count number of lines for each thr ; Each content will start with number (1: and finish with some numebr
thr=19068 ; Count 4
thr=55528 ; Count 2
答案1
awk -F'[]=[]' '
function print_count() {
printf "thr=%d ; Count %d\n", key, count
}
$2 == "thr" {if (key) print_count(); key = $3; count = 0; next}
{count++}
END {print_count()}
' file
这使用]
or=
或[
作为字段分隔符。
答案2
另一个 awk :
awk -F'[][]' '
function p_c () {
print a" ; Count "b
}
NF == 3 {
if ( f )
p_c()
a = $2
f = 1
next
}
{
b = $1
sub ( ":.*" , "" , b )
}
END {
p_c()
}
' infile
答案3
另一种awk
解决方案利用定义记录和字段分隔符:
$ awk -v RS="[0-9]+[[]" -v FS="\n" -v OFS=";" '$0 {gsub(/[]].*/, "", $1); print $1,"Count "NF-2}' input