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文件中的行范围

tag-icon • tag-icon text-processing awk sed grep perl
文件中的行范围

我有一个包含几行的文件：

  C   1.31729690416596     -0.05166770188922      0.05026556004853
  C   2.15676687192808     -0.87605403673920      0.93010807487406
  C   1.45516592682388     -0.49804136618225     -1.24011085742027
  C   2.67489108786199     -2.06116694592319      0.09667460087481
  C   2.24626744432148     -1.81826783081380     -1.24626795859707
  C   0.12278380551129     -0.78127661791244     -1.79035714840462
  C   0.11627012096698     -2.05095769577445     -2.31049614254010
  C   1.41908665901196     -2.77247309785857     -1.91624359298119

我需要在一次操作中打印一系列复杂的行，例如第 1 行和第 4 到 7 行，这是 1,4-7。如何获取这些行而不是逐行搜索。

答案1

ed行编辑器：

printf '%s\n' '1p' {4..7}p 'Q' | ed -s - file

awk:

printf 'NR==%d\n' 1 {4..7} | awk -f - file

sed流编辑器：

printf '%sp\n' 1 4,7 | sed -nf - file

perl:

perl -lne 'print if grep { $_ == $. } (1, 4..7)' file

答案2

使用awkvar NR：


awk 'NR == 1 ||  NR >= 4 && NR <= 7' file
  C   1.31729690416596     -0.05166770188922      0.05026556004853
  C   2.67489108786199     -2.06116694592319      0.09667460087481
  C   2.24626744432148     -1.81826783081380     -1.24626795859707
  C   0.12278380551129     -0.78127661791244     -1.79035714840462
  C   0.11627012096698     -2.05095769577445     -2.31049614254010

答案3

命令

sed -n -e '1p' -e '4,7p' filename

输出

 C   1.31729690416596     -0.05166770188922      0.05026556004853
  C   2.67489108786199     -2.06116694592319      0.09667460087481
  C   2.24626744432148     -1.81826783081380     -1.24626795859707
  C   0.12278380551129     -0.78127661791244     -1.79035714840462
  C   0.11627012096698     -2.05095769577445     -2.31049614254010

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