使用 Bash 脚本来检查名称列表与防火墙配置文件

Question 1

这是一个可以完成这个工作的 perl 脚本（据我所知）：

#!/usr/bin/perl
use strict;
use warnings;

my $config  = 'config.txt';   # give the full path
my $list    = 'list.txt';     # give the full path
my $outfile = 'outfile.txt';  # give the full path

# read list file and store in a hash
open my $fhl, '<', $list or die "unable to open '$list': $!";
my %users;
while(my $line = <$fhl>) {
    next if $. < 3;     # skip first 2 lines (header)
    my ($user, $name) = split(/\s+/, $line);
    $users{$user} = $name if $user and $name;
}
close $fhl;

open my $fhc, '<', $config or die "unable to open '$config': $!";
open my $out, '>', $outfile or die "unable to open '$outfile': $!";
# read config line by line
while(my $line = <$fhc>) {
    # loop on all users
    while( my ($u,$n) = each(%users)) {
        # print outputfile if user found 
        print $out "$u:$n found line $.\n" if $line =~ /\b($u|$n)\b/;
    }
}

给定示例的输出文件

test38:confidential2 found line 30
test47:confidential3 found line 32

Answer

这是一个可以完成这个工作的 perl 脚本（据我所知）：

#!/usr/bin/perl
use strict;
use warnings;

my $config  = 'config.txt';   # give the full path
my $list    = 'list.txt';     # give the full path
my $outfile = 'outfile.txt';  # give the full path

# read list file and store in a hash
open my $fhl, '<', $list or die "unable to open '$list': $!";
my %users;
while(my $line = <$fhl>) {
    next if $. < 3;     # skip first 2 lines (header)
    my ($user, $name) = split(/\s+/, $line);
    $users{$user} = $name if $user and $name;
}
close $fhl;

open my $fhc, '<', $config or die "unable to open '$config': $!";
open my $out, '>', $outfile or die "unable to open '$outfile': $!";
# read config line by line
while(my $line = <$fhc>) {
    # loop on all users
    while( my ($u,$n) = each(%users)) {
        # print outputfile if user found 
        print $out "$u:$n found line $.\n" if $line =~ /\b($u|$n)\b/;
    }
}

给定示例的输出文件

test38:confidential2 found line 30
test47:confidential3 found line 32

Question 2

根据我对您的请求的个人理解，我使用内置命令while和命令awk来解决它。

直接输出

awk 'NR>2{print $1,$2}' list.txt | while IFS=" " read -r username fullname; do awk -v name="${username}" 'BEGIN{OFS="|"}match($0,/'"${fullname}"'/){gsub(/>/,"",name);print name,NR,$0}' config.txt; done

将输出写入文件output.txt

awk 'NR>2{print $1,$2}' list.txt | while IFS=" " read -r username fullname; do awk -v name="${username}" 'BEGIN{OFS="|"}match($0,/'"${fullname}"'/){gsub(/>/,"",name);print name,NR,$0>>"output.txt"}' config.txt; done

输出格式为

user name|line no.|match content

结果输出

test16|64|>access-group vlan4_access_in in interface vlan004_confidential1
test38|30|> object network confidential2
test38|65|>access-group vlan65_access_in in interface vlan065_confidential2
test47|32|> object network confidential3
test47|66|>access-group vlan66_access_in in interface vlan066_confidential3
test85|67|>access-group vlan80_access_in in interface vlan080_confidential4

Answer

根据我对您的请求的个人理解，我使用内置命令while和命令awk来解决它。

直接输出

awk 'NR>2{print $1,$2}' list.txt | while IFS=" " read -r username fullname; do awk -v name="${username}" 'BEGIN{OFS="|"}match($0,/'"${fullname}"'/){gsub(/>/,"",name);print name,NR,$0}' config.txt; done

将输出写入文件output.txt

awk 'NR>2{print $1,$2}' list.txt | while IFS=" " read -r username fullname; do awk -v name="${username}" 'BEGIN{OFS="|"}match($0,/'"${fullname}"'/){gsub(/>/,"",name);print name,NR,$0>>"output.txt"}' config.txt; done

输出格式为

user name|line no.|match content

结果输出

test16|64|>access-group vlan4_access_in in interface vlan004_confidential1
test38|30|> object network confidential2
test38|65|>access-group vlan65_access_in in interface vlan065_confidential2
test47|32|> object network confidential3
test47|66|>access-group vlan66_access_in in interface vlan066_confidential3
test85|67|>access-group vlan80_access_in in interface vlan080_confidential4

使用 Bash 脚本来检查名称列表与防火墙配置文件

答案1

答案2

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