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打印表格中的数字

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打印表格中的数字

请问如何从这个表中得到四个数字？原始输入较长，因此需要限制区域。

输入：

chil           2   44843.084886752418        44843.080972494339       0.38261625919046571     

o 0  1 0 1 1      5.732820000     0.000 = PERIOD(0)
o 0  2 0 1 1  54002.864912732     0.000 = PERIASTRON EPOCH
o 0  3 0 1 1      0.086796671     0.000 = ECCENTRICITY
o 0  4 0 1 1    151.562809500     0.020 = PERIASTRON LONG.
o 0  5 0 1 1    107.927001263     0.053 = K1
o 0  6 0 1 1      0.418206121     0.000 = q = M2/M1,  K2 =  258.071309
o 0  7 0 1 1      0.004220000     0.000 = d omega/dt
o 0  8 0 1 1      0.000000000     0.100 = d P/dt
o 0  9 0 1 1      0.000000000     0.100 = d e/dt
o 0 10 0 1 1      0.000000000     0.100 = d K1/dt
o 0 11 0 1 1      0.000000000     0.100 = d q/dt

o 2  1 0 1 1  99000.000000000  1650.000 = PERIOD(2)
o 2  2 0 1 1  39254.892879388  -984.000 = PERIASTRON EPOCH
o 2  3 0 1 1      0.770000000     0.010 = ECCENTRICITY
o 2  4 0 1 1     68.284996369    -6.000 = PERIASTRON LONG.

所需输出

0.086796671
151.562809500
107.927001263
0.418206121

我尝试失败

/o 0  1 0 1 1      5.732820000     0.000 = PERIOD(0)/ { c=FNR;}
(FNR-c>=2 && c>0) {$2 ~ /\<0\>/ $3 ~ /\<3|4|5|6\>/ { print $7}

我想说：如果第二列是0，第三列是3,4,5,6打印第7列

答案1

awk '$2==0 && $3~/^[3456]$/{print $7}' data

更新

限制到特定区域：

awk '/o 0  1 0 1 1      5.732820000     0.000 = PERIOD\(0\)/ {b=1}
     b && $2==0 && $3~/^[3456]$/{print $7}
     b && $3==6 { b=0 }' data

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