因此我在 Mac Bash 中运行以下命令:
Callums-MacBook-Pro-2:chart melman$ helm list
NAME REVISION UPDATED STATUS CHART APP VERSION NAMESPACE
dozing-sasquatch 1 Fri Sep 13 11:31:40 2019 FAILED pointsapp-0.1.0 1.0.0 default
exasperated-boxer 1 Fri Sep 13 11:04:56 2019 FAILED pointsapp-0.1.0 1.0.0 default
foolhardy-arachnid 1 Fri Sep 13 10:47:45 2019 FAILED pointsapp-0.1.0 1.0.0 default
harping-ant 1 Fri Sep 13 09:44:07 2019 FAILED pointsapp-1.0.0 1.0.0 default
jazzed-gecko 1 Fri Sep 13 10:41:47 2019 FAILED pointsapp-1.0.0 1.0.0 default
luminous-rattlesnake 1 Fri Sep 13 10:51:44 2019 FAILED pointsapp-0.1.0 1.0.0 default
oily-deer 1 Fri Sep 13 10:58:17 2019 DEPLOYED pointsappv2-0.1.0 1.0 default
old-greyhound 1 Fri Sep 13 11:27:36 2019 FAILED pointsapp-0.1.0 1.0.0 default
plinking-llama 1 Fri Sep 13 11:19:23 2019 FAILED pointsapp-0.1.0 1.0.0 default
pugnacious-numbat 1 Fri Sep 13 10:07:04 2019 FAILED pointsapp-1.0.0 1.0.0 default
telling-skunk 1 Fri Sep 13 10:05:35 2019 FAILED pointsapp-1.0.0 1.0.0 default
torpid-gopher 1 Fri Sep 13 10:46:49 2019 FAILED pointsapp-0.1.0 1.0.0 default
我如何选择所有名称并将它们传递给helm delete [name]
,这可以在单个命令中完成吗?
答案1
假设所有名称都不包含空格,您可以使用循环for
来循环遍历列表行,通过管道跳过tail
标题行,然后awk
仅打印第一列:
for name in $(helm list | tail -n+2 | awk '{print $1}'); do helm delete $name; done
您确实要删除整个列表吗?
E:若要仅删除失败的,请输入grep
:
for name in $(helm list | tail -n+2 | grep "FAILED" | awk '{print $1}'); do helm delete $name; done