我拥有的：
X
(
1
2
3
)
BREAK
Y
(
4
5
)
BREAK
Z
(
6
7
8
9
)
BREAK
我想要的是：
X,1
X,2
X,3
Y,4
Y,5
Z,6
Z,7
Z,8
Z,9
我更愿意弄清楚如何使用 Notepad++ 中的 RegEx 来执行此操作。据我了解，我需要在“查找”文本框中输入类似以下内容：
^(.*?)\((.*?)\).*?BREAK
被Search Mode存在Regular Expression并被. matches newline选中。
但我不知道在“查找/替换”输入框的“替换”部分中输入什么。
\r\n我如何指定要用之前捕获的字符（X，Y或）替换两个括号之间的每个实例Z？
答案1
我假设您的X、Y、Z是单词，1、2、3是数字。如果不是这样，请将下面的内容替换\w+为您需要的任何字符类，并将下面的内容替换\d+为您需要的任何字符类。
- Ctrl+H
- 找什么：
^(\w+)\R\(\R(\d+\R)(?:(\d+\R))?(?:(\d+\R))?(?:(\d+\R))?(?:(\d+\R))?\)\RBREAK - 用。。。来代替：
$1,$2(?3$1,$3)(?4$1,$4)(?5$1,$5)(?6$1,$6) - 查看 环绕
- 查看 正则表达式
- Replace all
解释：
^ # beginning of line
(\w+) # group 1, 1 or more word character, you can use the character class you need
\R # any kind of linebreak
\( # an opening parenthesis
\R # any kind of linebreak
( # start group 2
\d+ # 1 or more digits, you can use the character class you need
\R # any kind of linebreak
) # end group 2
(?: # non capture group
(\d+\R) # group 3, same pattern as group 2
)? # end non capture group, optional
(?:(\d+\R))? # same as above, group 4
(?:(\d+\R))? # same as above, group 5
(?:(\d+\R))? # same as above, group 6
You can add more structures as above depending on max number of lines you have.
\) # closing parenthesis
\R # any kind of linebreak
BREAK # literally
替代品：
$1,$2 # content of group 1, comma, content of group 2
(?3 # if group 3 exists then:
$1,$3 # content of group 1, comma, content of group 3
) # endif
(?4$1,$4) # same as above for group 4
(?5$1,$5) # same as above for group 5
(?6$1,$6) # same as above for group 6
Add as many similar structures as above depending on max number of lines you have.
截图（之前）：
截图（之后）：
