有一个带有 vname 和 vport 的 file1
Vname vport
xyc 3:4:7
sdf 5:5:5
sft 5:5:5
sfg 3:4:7
szd 1:2:3
获取唯一端口
vport 1:2:3
将它们分开并分配给一个变量,例如 a=1, b=2, c=3
答案1
这回答了你的问题了吗?
#!/bin/bash
# IFS is a special enviroment variable. The character in it will be used
# by 'read' (which is a bash builtin command).
#
# In this case we need space and colon as separators
#
IFS=' :'
# Looping over lines in the file, fo each line read name, a, b, and c.
# "sed 1d" command deletes first line to skip over header ("Vname vport")
#
sed 1d file1 | while read name a b c ; do
# If it was an empty line, skip and loop to next line
#
[ "$name" ] || continue
# output the variables for demonstration
#
echo "name: $name"
echo "a = $a"
echo "b = $b"
echo "c = $c"
# extra line to separate output of next line
#
echo
done
答案2
我假设您想要识别vport
在文件中只出现一次的组合,并且想要将其拆分为三个变量a
、b
和c
。在这种情况下,您可以使用关联数组:
以下应该有效:
#!/bin/bash
declare -A counts # declare `counts` as associative container
# Read the file line-wise
while read vname vport
do
if [[ "$vname" == "Vname" ]]; then continue; fi # skip header
# if current 'vport' value not yet encountered, add it to the array
# with count=1, otherwise increment the value
if [[ -z "${counts[$vport]}" ]]
then
counts[$vport]=1
else
let counts[$vport]=${counts[$vport]}+1
fi
done < file.txt
# Identify which one only occurs once: iterate over all "keys" and
# check which "value" is "1"
found=0
for vp in "${!counts[@]}"
do
# If such a key was found, split it at the ':' and read the parts
# into individual variables
if [[ "${counts[$vp]}" == "1" ]]
then
IFS=":"
read a b c <<< "$vp"
found=1
break
fi
done
# Output the variables if a unique port specification was found
if (( found == 1 ))
then
echo "Unique port found: a=$a, b=$b, c=$c"
else
echo "No unique port found!"
fi
笔记这假设有只有一个这样独特的港口(从你的例子中猜测似乎是合理的)。