Notepad ++ / 提取 ^ ^ 之间的文本并将其添加为新行

Question

我有一个文本文件，需要从中提取特定的数据元素（将人员全名添加为新行）：

ID:363712^CLARK/DEJA G^:e30276c2f826febd3784958:KZxhnbUUouxvMrTEYfGnDZ7YcGjPh

ID:363713^LUTZ/ANTON A^:84cF6F48eAc2b5E223Bf1703:ZD4LLGMqNyNYYtjLycdEds23A2

ID:363714^OATO/GINA D^:GnDZ7YcGjPh6Ru7cEjfQGZgD:GMqNyNYYtjLycdEdcxRijNc7G

---

我想要提取：

DEJA G CLARK
ID:363712^CLARK/DEJA G^:e30276c2f826febd3784958:KZxhnbUUouxvMrTEYfGnDZ7YcGjPh

安东·A·卢茨
ID:363713^LUTZ/安东·A^:84cF6F48eAc2b5E223Bf1703:ZD4LLGMqNyNYYtjLycdEds23A2

GINA OATO
ID：363714^OATO/GINA^：GnDZ7YcGjPh6Ru7cEjfQGZgD：GMqNyNYYtjLycdEdcxRijNc7G

问候

Answer 1

1. 按 Ctrl+H
2. 找什么：(.+\^)(.+)(\/)(.+)(\^.+)
3. 用。。。来代替：$4 $2\n$1$2$3$4$5
4. 搜索模式：正则表达式
5. 按“全部替换”

前

后

Answer 2

• Ctrl+H
• 找什么：^.+?\^(.+?)/(.+?)\^.+$
• 用。。。来代替：$2 $1\n$0
• 查看 环绕
• 查看 正则表达式
• 取消选中 . matches newline
• Replace all

解释：

^           # beginning of line
    .+?         # 1 or more any character but newline, not greedy
    \^          # carret, have to be escaped as it's a special character for regex
    (.+?)       # group 1, 1 or more any character but newline, not greedy
    /           # a slash
    (.+?)       # group 2, 1 or more any character but newline, not greedy
    \^          # carret, have to be escaped as it's a special character for regex
    .+          # 1 or more any character but newline
$           # end of line

替代品：

$2          # content of group 2 (firstname initial) followed by a space
$1          # content of group 1 (lastname)
\n          # linefeed, you may use \r\n for Windows EOL
$0          # the whole match (i.e. the whole line)

截图（之前）：

截图（之后）：