我有 2 个段落，带有 html 标签<p class="mb-40px"></p>此标签内有文本和另一个 <p..> 标签
我需要查找并删除主标签中包含的 html 标签<p class="mb-40px"></p>
例子：
<p class="mb-40px">Miracles every day <p lang="ro-RO" align="JUSTIFY">being at la home, the poet Petru Iliesu made an international appeal to condemn the killing of demonstrators, shot on the streets of town.</p>
<p class="mb-40px">The pleasure we feel after reading a book is different from the pleasure of tasting a dish <p class="dis23">. In the first case, pleasure is disinterested, having no particular purpose, as a release from external preoccupations.</p>
输出
<p class="mb-40px">Miracles every day being at la home, the poet Petru Iliesu made an international appeal to condemn the killing of demonstrators, shot on the streets of town.</p>
<p class="mb-40px">The pleasure we feel after reading a book is different from the pleasure of tasting a dish. In the first case, pleasure is disinterested, having no particular purpose, as a release from external preoccupations.</p>
我的正则表达式不太好：
寻找： (?:<p class="mb-40px">|\G)\S*\K(?:\h+<\s*(\w+)[^/>]*>)(?=.*</p>)
替换为：（留空）
答案1
这是您修改后的公式，对我而言有效：
<p class="mb-40px">.*\K(?:\h+<\s*(\w+)[^\/>]*>)(?=.*<\/p>)
- 你不需要使用
?:<，\G如果你无论如何使用\K \S*.*仅当标签之间只有一个单词且没有空格时才有效，请使用/需要转义：\/
下面是一个更短的表达式：
<p class="mb-40px">.*\K<p[^>]+>
答案2
是的，我设法自己找到解决方案：
寻找：(?-i:<p class="mb-40px">|\G(?!^))(?s:(?!</p>).)*?\K(?-i:<\s*(\w+)[^/>]*>)
替换为：LEAVE EMPTY
因此，如果我想查找/替换其他两个部分中的内容，通用正则表达式将是：
(?-i:REGION-START|\G(?!^))(?s:(REGION-FINAL).)*?\K(?-i:FIND REGEX)