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如何对 grep 结果进行分组？

tag-icon • tag-icon bash grep
如何对 grep 结果进行分组？

我有一个文件，其中包含按类别分组的结果。例如：

checking results for $var
here are some results1 for $var status ok
here are some results2 for $var status ok
here are some results3 for $var status ok

checking results for $var2
here are some results1 for $var2 status ok

checking results for $var3
here are some results1 for $var3 status ok
here are some results2 for $var3 status ok
here are some results3 for $var3 status critical
here are some results4 for $var3 status ok

我需要检查给定类别中的任何行是否具有“关键”状态，如果是，则显示它。例如：

Status $var -- OK
Status $var2 -- OK
Status $var3 -- Critical

Note : Critial at $result3 for $var3

使用grep -A不太适合我，因为特定变量下的结果数量各不相同。

答案1

awk 会这样做：

awk '
    BEGIN {
        priority["ok"] = 10
        priority["critical"] = 20
    }
    /^$/ {next}
    /^checking/ {var = $NF}
    {
        if (priority[status[var]] < priority[$NF])
            status[var] = $NF
        if ($NF == "critical")
            crit[var ":" $4] = 1
    }
    END {
        for (var in status)
            print var, status[var]
        for (c in crit) {
            split(c, ary, /:/)
            printf("critical at %s for %s\n", ary[2], ary[1])
        }
    }
'

输出

$var ok
$var2 ok
$var3 critical
critical at results3 for $var3

答案2

我会使用 awk 脚本：

/^checking results for / {
    if (curvar) { print curvar, curstatus; }
    curvar = $NF
    curstatus = "ok"
}
/^here are some results.* for .* status / {
    if ($NF != "ok") { curstatus = $NF; 
}
END {
    if (curvar) { print curvar, curstatus; }
}

您可以使用数组来构建“不良结果”表。

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