☰

将列中的数据转换为 json

tag-icon • tag-icon json
将列中的数据转换为 json

我的文本文件中的数据格式为：

alex street1 253465873 [email protected]
john street2 442893646 [email protected]
kevin street3 125234763 [email protected]

我需要将此数据转换为带有标头的 json 格式： "name" "street" "phone" "e-mail"

答案1

你可以阅读原始输入并将其分割为空格分隔的字段，jq如下所示：

$ cat file.txt | 
    jq -nR '[inputs | split(" ") | { "name": .[0], "street": .[1], "phone": .[2], "e-mail": .[3] }]'
[
  {
    "name": "alex",
    "street": "street1",
    "phone": "253465873",
    "e-mail": "[email protected]"
  },
  {
    "name": "john",
    "street": "street2",
    "phone": "442893646",
    "e-mail": "[email protected]"
  },
  {
    "name": "kevin",
    "street": "street3",
    "phone": "125234763",
    "e-mail": "[email protected]"
  }
]

或者，对于简单（非嵌套）表格数据，您可以使用磨坊主

mlr --inidx --ojson --jvstack rename '1,name,2,street,3,phone,4,e-mail' file.txt

答案2

$ column --table --separator=" " --table-columns name,street,phone,email --json test.txt

{
   "table": [
      {
         "name": "alex",
         "street": "street1",
         "phone": "253465873",
         "email": "[email protected]"
      },{
         "name": "john",
         "street": "street2",
         "phone": "442893646",
         "email": "[email protected]"
      },{
         "name": "kevin",
         "street": "street3",
         "phone": "125234763",
         "email": "[email protected]"
      }
   ]
}

答案3

使用磨坊主( mlr) 将无标头和空格分隔的数据转换为 JSON：

$ mlr --n2j label name,street,phone,e-mail file
{ "name": "alex", "street": "street1", "phone": 253465873, "e-mail": "[email protected]" }
{ "name": "john", "street": "street2", "phone": 442893646, "e-mail": "[email protected]" }
{ "name": "kevin", "street": "street3", "phone": 125234763, "e-mail": "[email protected]" }

输出是每个输入记录的单独 JSON 对象。该选项是（“输入是隐式整数索引（nidx）”）与（“输出是 JSON”）--n2j的简写。--inidx--ojson

该label子命令按顺序重命名字段。

您想将生成的对象集包装在数组中，请使用--jlistwrap：

$ mlr --n2j --jlistwrap label name,street,phone,e-mail file
[
{ "name": "alex", "street": "street1", "phone": 253465873, "e-mail": "[email protected]" }
,{ "name": "john", "street": "street2", "phone": 442893646, "e-mail": "[email protected]" }
,{ "name": "kevin", "street": "street3", "phone": 125234763, "e-mail": "[email protected]" }
]

答案4

试试这个 awk 命令：

$ awk '{for (i=1;i<=NF;i++){$i="\""$i"\"";printf $i" "}};{printf"\n"}' infile

"alex" "street1" "253465873" "[email protected]" 
"john" "street2" "442893646" "[email protected]" 
"kevin" "street3" "125234763" "[email protected]"

相关内容