编写创建硬链接的脚本，根据现有文件名以及是否满足某些条件对它们进行编号？

Question

基本上：您需要一个带有 N 个参数的脚本，第一个可以是生成的 HardlinkDir，然后是包含剧集名称的文件，其余的可以是 dirA、dirB、dirC 等。

对我来说，最简单的是 1) 删除 HardlinkDir 目录的内容，然后对于 dirA、dirB dirC 中按字母顺序看到的每个文件：在该文件中。标题可以来自一个单独的文件，给出您希望第 N 个文件具有的名称？

IE：

文件“series_name.txt”，您可以在其中按顺序放置所有剧集名称，每行 1 个。举个例子：

 s01e01 - Episode Name
 s01e02 - Episode Name
 etc.

以及您为其提供参数的脚本：“HardlinkDir”“series_name.txt”“dirA”“dirB”“dirC”（...）

bash 的一个简单解决方案（调用 awk 脚本来完成繁重的工作）是：

#!/usr/bin/env bash
_usage() {
  cat <<'EOF'
   this script needs at least those arguments:
     # $1=HardLinkDir, $2=series_name.txt # containing 1 line per episode name
     # $3 to $n : the directory, in order, with the *.mp4 and *.mkv in them, in order
   it will then EMPTY the $1 directory, and re-create hard links (ln) in it.
EOF
   for msg in "$@"; do printf "Erreur: %s\n" "$msg" ; done
   exit 1
}

if [ "$#" -lt 3 ]; then
   _usage "We need at least 3 args : HardLinkDir series_name.txt dirA ... "
fi
lndir="$1" ; 
episode_list="$2" ; series_name="${2/.txt/}" ; 
[ -d "$lndir" ] || _usage "arg1 : lndir=$lndir : is not a directory"
[ -f "$episode_list" ] || _usage "arg2 : episode_list=$episode_list : is not a file"
shift 2 # we "absorbed" the first 2 args : the rest are the dirs with the movie files
arg=2
for dir in "$@"; do 
  arg=$((arg + 1))
  [ -d "$dir" ] || _usage "arg${arg}: '$dir' : is not a directory."
done  

rm "${lndir:-__must_be_nonvoid__}"/*  # delete first the files in that dir, if any

for dir in "$@"; do
  ls "${dir}"/*.???
done | awk -v series_name="${series_name}" -v lndir="${lndir}" '
 BEGIN { after_first=0 }
 (NR == FNR) { rem="we read the first file... so the episode list"
               episode[NR]=$0
 }

 ((NR != FNR) && ( after_first==0 )) { after_first=1; episode_number=0 }

 ((NR != FNR) && ( $0 ~ /..mp4|.mkv/ ) { 
   rem="NR>FNR, so we read the 2nd file, -, stdin..."
   rem="we also match .mp4 or .mkv, so we have a video file fullname as input"
   episode_number++
   fullfilename=$0; ext=fullfilename ; sub(".*[.]","",ext)
   destname = lndir "/" series_name " - " episode[episode_number] "." ext
   cmd="ln \"" fullfilename "\" \"" destname "\""
   printf("executing: %s\n",cmd)
   system(cmd); close(cmd)
 }
' "$episode_list" "-"  # first file is the episode_list file, then stdin

请注意：我只是写了这个，根本没有测试它，因为我现在无法测试它......也许将上面的“rm”和“ln”分别替换为：“echo rm”和“echo ln”，以看看会做什么...我也只使用常规的 awk 想法（因此很奇怪： ext=fullname; sub(....,ext) ）

Answer 1