使用awk计算不同列数的每一行的平均值

使用awk计算不同列数的每一行的平均值

是否可以用来awk计算平均的每行的(每行有不同的列)。我有一个如下所示的文件,第一列是名称,我喜欢计算每行的平均值并将结果打印在输入文件的最后一列中:

输入文件( data1.csv):

EMPLOYEE1,0.395314,0.384513,,
EMPLOYEE2,5.4908,5.2921,,
EMPLOYEE3,0.0002323,0.00022945,0.00023238,0.00022931
EMPLOYEE4,0.00335516,0.00328432,0.00340309,0.00327163
EMPLOYEE5,1.4816,1.4367,1.4854,1.4353
EMPLOYEE6,7.89E-06,7.93E-06,7.95E-06,7.87E-06
EMPLOYEE7,3.724E-06,3.8745E-06,3.9428E-06,3.7227E-06
EMPLOYEE8,0.699498,0.688892,0.704256,0.683486
EMPLOYEE9,33.5195,31.9736,33.6779,31.742

期望的输出:

EMPLOYEE1,0.395314,0.384513,,,0.3899135
EMPLOYEE2,5.4908,5.2921,,,5.39145
EMPLOYEE3,0.0002323,0.00022945,0.00023238,0.00022931,0.00023086
EMPLOYEE4,0.00335516,0.00328432,0.00340309,0.00327163,0.00332855
EMPLOYEE5,1.4816,1.4367,1.4854,1.4353,1.45975
EMPLOYEE6,7.89E-06,7.93E-06,7.95E-06,7.87E-06,7.91E-06
EMPLOYEE7,3.72E-06,3.87E-06,3.94E-06,3.72E-06,3.82E-06
EMPLOYEE8,0.699498,0.688892,0.704256,0.683486,0.694033
EMPLOYEE9,33.5195,31.9736,33.6779,31.742,32.7282

我尝试了 awk如下操作,但它不会计算列小于最大 NF 的行的平均值。

awk  -F',' '{ s = 0; for (i = 2; i <= NF; i++) s += $i; print $1, (NF > 1) ? s / (NF - 1) : 0; }'  data1.csv

 awk -F','  '{sum=0; for (i=2;i<=NF;i++)sum+=$i; print $0,sum/(NF-1)}'  data1.csv

但我的代码没有改变 NF 行。是否可以更改每一行的 NF 并获得所需的输出?

答案1

这是一种方法:

$ awk -F',' -v OFS=',' '{ 
        s=0; 
        numFields=0; 
        for(i=2; i<=NF;i++){ 
            if(length($i)){ 
                s+=$i; 
                numFields++
            } 
        } 
        print $0, (numFields ? s/numFields : 0)}' data1.csv 
EMPLOYEE1,0.395314,0.384513,,,0.389914
EMPLOYEE2,5.4908,5.2921,,,5.39145
EMPLOYEE3,0.0002323,0.00022945,0.00023238,0.00022931,0.00023086
EMPLOYEE4,0.00335516,0.00328432,0.00340309,0.00327163,0.00332855
EMPLOYEE5,1.4816,1.4367,1.4854,1.4353,1.45975
EMPLOYEE6,7.89E-06,7.93E-06,7.95E-06,7.87E-06,7.91e-06
EMPLOYEE7,3.724E-06,3.8745E-06,3.9428E-06,3.7227E-06,3.816e-06
EMPLOYEE8,0.699498,0.688892,0.704256,0.683486,0.694033
EMPLOYEE9,33.5195,31.9736,33.6779,31.742,32.7282

请注意,awk 打印的0.389914结果0.779827/2意味着第一行的平均值将是0.389914,而不是0.389915。这是因为 awk 会四舍五入到最接近的偶数,并且它的默认打印模式(由变量控制OFMT)是%0.6g。如果您需要更高的准确性,您可以这样做:

$ awk -F',' -v OFS=',' -v OFMT='%0.7g' '{ 
        s=0; 
        numFields=0; 
        for(i=2; i<=NF;i++){ 
            if(length($i)){ 
                s+=$i; 
                numFields++
            } 
        } 
        print $0, (numFields ? s/numFields : 0)}' data1.csv 
EMPLOYEE1,0.395314,0.384513,,,0.3899135
EMPLOYEE2,5.4908,5.2921,,,5.39145
EMPLOYEE3,0.0002323,0.00022945,0.00023238,0.00022931,0.00023086
EMPLOYEE4,0.00335516,0.00328432,0.00340309,0.00327163,0.00332855
EMPLOYEE5,1.4816,1.4367,1.4854,1.4353,1.45975
EMPLOYEE6,7.89E-06,7.93E-06,7.95E-06,7.87E-06,7.91e-06
EMPLOYEE7,3.724E-06,3.8745E-06,3.9428E-06,3.7227E-06,3.816e-06
EMPLOYEE8,0.699498,0.688892,0.704256,0.683486,0.694033
EMPLOYEE9,33.5195,31.9736,33.6779,31.742,32.72825

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