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rsync 传递多个从 $@ 排除的内容

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rsync 传递多个从 $@ 排除的内容

我正在尝试围绕 rsync 命令制作一个包装器以重用代码。我需要传递源文件夹、目标文件夹，然后传递任意数量的排除目录。这是我的日志；基本上我正在构建我的多个 rsync --从我的“vararg”参数中排除参数。可能有更好的方法，但我发现一个就足够了。

function run_backup(){
    source="$1"
    target="/backups/unraid$2"
    #Copying $source into remote folder $target

    # Building my exclude params
    if [ $# -ge 3 ]; then
        excludes="--exclude '$3'"
        while shift && [ -n "$3" ]; do
            echo $excludes
            excludes="${excludes} --exclude '$3'"
        done
    else
        excludes = "--exclude '/tmp'" # Dummy exclude; I'll handle this case later
    fi
    echo $excludes
    
    # Creating folder because rsync crash otherwise n some case
    ssh -p 22 -i /home/backup/.ssh/mykey [email protected] "mkdir -p $target"

    # Executing the copy
    set -e
    sudo rsync -azvh \
        -e "ssh  -p 22-i /home/backup/.ssh/mykey "\
        --progress \
        --delete \
        $excludes \
        $source \
        [email protected]:$target
}


mkdir -p /tmp/dummy
echo "dummy" > /tmp/dummy/save-ignored-1
echo "dummy" > /tmp/dummy/save-ignored-2
echo "dummy" > /tmp/dummy/save-test
run_backup /tmp/dummy/ /dummy /tmp/dummy/save-ignored-1 /tmp/dummy/save-ignored-2 /tmp/toto /tmp/tata /tmp/tutu #TODO

--exclude '/tmp/dummy/save-ignored-1'
--exclude '/tmp/dummy/save-ignored-1' --exclude '/tmp/dummy/save-ignored-2'
--exclude '/tmp/dummy/save-ignored-1' --exclude '/tmp/dummy/save-ignored-2' --exclude '/tmp/toto'
--exclude '/tmp/dummy/save-ignored-1' --exclude '/tmp/dummy/save-ignored-2' --exclude '/tmp/toto' --exclude '/tmp/tata'
--exclude '/tmp/dummy/save-ignored-1' --exclude '/tmp/dummy/save-ignored-2' --exclude '/tmp/toto' --exclude '/tmp/tata' --exclude '/tmp/tutu'
++ ssh -p 22-i /home/backup/.ssh/mykey [email protected] 'mkdir -p /backups/unraid/dummy'
++ sudo rsync -azvh -e 'ssh  -p 22 -i /home/backup/.ssh/mykey' --progress --delete --exclude ''\''/tmp/dummy/save-ignored-1'\''' --exclude ''\''/tmp/dummy/save-ignored-2'\''' --exclude ''\''/tmp/toto'\''' --exclude ''\''/tmp/tata'\''' --exclude ''\''/tmp/tutu'\''' /tmp/dummy/ [email protected]:/backups/unraid/dummy

我们可以看到 var$excludes正是我想要的；但是当我将它传递给 rsync 时，bash 正在对它施展一些魔法。我不知道如何避免这种情况。我想这与扩展有关，但我找不到与我的或相关文档类似的问题。

编辑：第一个答案后的代码：

function run_backup(){
    excludes=()
    if [ $# -ge 3 ]; then
        echo $3
        excludes+=(--exclude $3)
        while shift && [ -n "$3" ]; do
            echo $3
            excludes+=(--exclude $3)
        done
    else
        excludes+=(--exclude /tmp)
    fi
    set -x
    echo "${excludes[@]}"
}
run_backup /tmp/dummy/ /dummy "/tmp/dummy/save-ignored" "/tmp/dummy/save non'standard ignored" /tmp/toto /tmp/tata /tmp/tutu

但它不适用于包含引号的字符串（至少是简单的引号）

/tmp/dummy/save-ignored
/tmp/dummy/save non'standard ignored
/tmp/toto
/tmp/tata
/tmp/tutu
++ echo --exclude /tmp/dummy/save-ignored --exclude /tmp/dummy/save 'non'\''standard' ignored --exclude /tmp/toto --exclude /tmp/tata --exclude /tmp/tutu
--exclude /tmp/dummy/save-ignored --exclude /tmp/dummy/save non'standard ignored --exclude /tmp/toto --exclude /tmp/tata --exclude /tmp/tutu

编辑2：无用;只是保留它作为历史 包含所有报价可能性的测试：

run_backup(){
    excludes=()
    excludes2=()
    excludes3=()
    if [ $# -ge 3 ]; then
        echo $3
        excludes+=(--exclude $3)
        excludes2+=(--exclude "$3")
        excludes3+=(--exclude "\"$3\"")
        while shift && [ -n "$3" ]; do
            echo $3
            excludes+=(--exclude $3)
            excludes2+=(--exclude "$3")
            excludes3+=(--exclude "\"$3\"")
        done
    else
        excludes+=(--exclude /tmp)
    fi
    set -x
    echo "${excludes[@]}"
    echo "${excludes2[@]}"
    echo "${excludes3[@]}"
     sudo rsync -azvh \
        --dry-run \
        "${excludes[@]}" \
        --dry-run \
        "${excludes2[@]}" \
        --dry-run \
        "${excludes3[@]}" \
        --dry-run \
        ${excludes[@]} \
        --dry-run \
        ${excludes2[@]} \
        --dry-run \
        ${excludes3[@]} \
        /tmp \
        [email protected]:/tmp
}
run_backup "/tmp/dummy/" "/dummy" "/tmp/dummy/save non'standard" "/tmp/toto"

++ echo --exclude /tmp/dummy/save 'non'\''standard' --exclude /tmp/toto
--exclude /tmp/dummy/save non'standard --exclude /tmp/toto
++ echo --exclude '/tmp/dummy/save non'\''standard' --exclude /tmp/toto
--exclude /tmp/dummy/save non'standard --exclude /tmp/toto
++ echo --exclude '"/tmp/dummy/save non'\''standard"' --exclude '"/tmp/toto"'
--exclude "/tmp/dummy/save non'standard" --exclude "/tmp/toto"
++ sudo rsync -azvh --dry-run --exclude /tmp/dummy/save 'non'\''standard' --exclude /tmp/toto --dry-run --exclude '/tmp/dummy/save non'\''standard' --exclude /tmp/toto --dry-run --exclude '"/tmp/dummy/save non'\''standard"' --exclude '"/tmp/toto"' --dry-run --exclude /tmp/dummy/save 'non'\''standard' --exclude /tmp/toto --dry-run --exclude /tmp/dummy/save 'non'\''standard' --exclude /tmp/toto --dry-run --exclude '"/tmp/dummy/save' 'non'\''standard"' --exclude '"/tmp/toto"' /tmp [email protected]:/tmp

我的测试的屏幕截图，具有更好的格式输出：我的测试的屏幕截图，具有更好的格式输出

答案1

使用数组而不是字符串。

例如：

opt=()
opt+=(--exclude "first")
opt+=(--exclude "another one")

set -x
echo "${opt[@]}"

这将正确处理空格（输出）：

+ echo --exclude first --exclude 'another one'

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