BASH - if 语句无法正常工作

Question

我运行了一次下面的脚本，当找到enforce_for_root匹配时，它已附加在行尾。但是，由于某种原因，即使该条目已经存在，pam_pwquality.so它仍会继续输入 if 。if ! grep -q "enforce_for_root" /etc/pam.d/system-auth

#!/bin/bash
source oem.properties

log_error() {
    echo "Error: $1" | /usr/bin/tee $ERROR_LOG
    echo "Aborting program ... "
    echo " "
    exit 10
}

echo " "
echo -n "Generating SSH keys ... "
if [ -f /home/rlee/.ssh/keys/$RSYNC_KEY ]; then
    echo "key exists, skipping."
else
    sudo -u rlee ssh-keygen -b 4096 -t $RSYNC_KEY_TYPE -f /home/rlee/.ssh/keys/$RSYNC_KEY -C "$RSYNC_KEY_COMMENT" -q -N ""
    if [ $? -ne 0 ]; then log_error "Generating SSH keys."; fi
    echo "OK"
fi
echo " "

echo "Add the public key to old OEM server."
echo "Create or modify the authorized_keys file on the old server."
echo "vim /home/rsync/.ssh/authorized_keys"
echo " "
echo "Add the following key: "
while true
do 
    cat /home/rlee/.ssh/keys/$RSYNC_KEY.pub
    echo " "
    read -p "Press 'C' to continue: " OPTION
    if [ $OPTION == 'C' ] || [ $OPTION == 'c' ]; then break; fi
done

echo -n "Testing SSH connection ... "
ssh -p $OLD_OEM_PORT -i /home/rlee/.ssh/keys/$RSYNC_KEY -o StrictHostKeyChecking=no rsync@$OLD_OEM_HOSTNAME exit
if [ $? -ne 0 ]; then log_error "Testing SSH connection ... "; fi
echo "OK"

useradd llee
useradd nagios

# Enforce password policies
echo -n "Setting password policies ... "
authconfig --enablereqlower --enablerequpper --enablereqdigit --enablereqother --passminlen=12 --passmaxrepeat=3 --update
if [ $? -ne 0 ]; then log_error "Setting password policies ... "; fi
echo "OK"

echo -n "Enforcing password policies on root ... "
if ! grep -q "enforce_for_root" /etc/pam.d/system-auth; then
    
    sed -i -e '/pam_pwquality.so/s/$/ enforce_for_root/' /etc/pam.d/system-auth
    echo "doesn't exist"
fi
if [ $? -ne 0 ]; then log_error "Enforcing password policies on root ... "; fi

exit 

如果我将此代码块移动到adduser语句之前的任何位置，它就不会if ! grep -q "enforce_for_root" /etc/pam.d/system-auth按预期工作。

为什么会发生这种情况？

#!/bin/bash

log_error() {
    echo "Error: $1" | /usr/bin/tee $ERROR_LOG
    echo "Aborting program ... "
    echo " "
    exit 10
}


echo -n "Enforcing password policies on root ... "
if ! grep -q "enforce_for_root" /etc/pam.d/system-auth; then
    
    sed -i -e '/pam_pwquality.so/s/$/ enforce_for_root/' /etc/pam.d/system-auth
    echo "doesn't exist"
fi
if [ $? -ne 0 ]; then log_error "Enforcing password policies on root ... "; fi

Answer 1

以下行导致了问题： authconfig --enablereqlower --enablerequpper --enablereqdigit --enablereqother --passminlen=12 --passmaxrepeat=3 --update

这是运行命令时收到的消息authconfig：

Running authconfig compatibility tool.
The purpose of this tool is to enable authentication against chosen services with authselect and minimum configuration. It does not provide all capabilities of authconfig.

IMPORTANT: authconfig is replaced by authselect, please update your scripts.
See man authselect-migration(7) to help you with migration to authselect

我已经修改了pwquality.conf文件

echo -n "Setting password policies ... "
sed -i -e '/# minlen =/s/# minlen/minlen/' /etc/security/pwquality.conf
sed -i -e '/# ucredit =/s/# ucredit/ucredit/' /etc/security/pwquality.conf
sed -i -e '/# lcredit =/s/# lcredit/lcredit/' /etc/security/pwquality.conf
sed -i -e '/# dcredit =/s/# dcredit/dcredit/' /etc/security/pwquality.conf
sed -i -e '/# ocredit =/s/# ocredit/ocredit/' /etc/security/pwquality.conf
sed -i -e '/# enforcing =/s/# enforcing/enforcing/' /etc/security/pwquality.conf
sed -i -e '/# enforce_for_root/s/# enforce_for_root/enforce_for_root/' /etc/security/pwquality.conf
sed -i -e 's/minlen = .*/minlen = 12/' /etc/security/pwquality.conf
sed -i -e 's/ucredit = .*/ucredit = 1/' /etc/security/pwquality.conf
sed -i -e 's/lcredit = .*/lcredit = 1/' /etc/security/pwquality.conf
sed -i -e 's/dcredit = .*/dcredit = 1/' /etc/security/pwquality.conf
sed -i -e 's/ocredit = .*/ocredit = 1/' /etc/security/pwquality.conf
echo "OK"