来自文档:
Changes the dimensions of the output picture. If the y value is
omitted, the x value will be used for both dimensions. Values
larger than 1 lead to a compressed screen (screen dimension big‐
ger than the dimension of the output mode), and values less than
1 lead to a zoom in on the output. This option is actually a
shortcut version of the --transform option.
咱们试试吧:
当我打字时,--xrandr --output eDP 1.2x1.2
屏幕会变小约 20%(这一点已验证)
当我打字时,--xrandr --output eDP 0.8x0.8
屏幕变得绝对巨大,放大了 20% 以上(这伪造了文档)
当我打字时,--xrandr --output eDP 1x1
它会变得更大!它正在放大。这些变换似乎是相对应用的......但如果是这种情况,那么 1x1 应该保持它完全静态?
当我打字时,--xrandr --output eDP 1.5x1.5
它又变小了。但它仍然大于--scale 1.2x1.2
,相对缩放的进一步证据。
当我打字时--xrandr --output eDP 1.5x1.5
什么也没有发生。等等——这是否意味着这些变换不是相对应用的?
当我打字时,--xrandr --output eDP 2x2
它基本上会回到原来的大小......这不是 2 倍比例! (原始尺寸为 1920x1080,缩放比例为 1 倍)。
--scale
的简写也是如此--transform
,其描述为:
--transform a,b,c,d,e,f,g,h,i
Specifies a transformation matrix to apply on the output. A bi‐
linear filter is selected automatically unless the --filter pa‐
rameter is also specified. The mathematical form corresponds
to:
a b c
d e f
g h i
The transformation is based on homogeneous coordinates. The ma‐
trix multiplied by the coordinate vector of a pixel of the out‐
put gives the transformed coordinate vector of a pixel in the
graphic buffer. More precisely, the vector (x y) of the output
pixel is extended to 3 values (x y w), with 1 as the w coordi‐
nate and multiplied against the matrix. The final device coordi‐
nates of the pixel are then calculated with the so-called ho‐
mogenic division by the transformed w coordinate. In other
words, the device coordinates (x' y') of the transformed pixel
are:
x' = (ax + by + c) / w' and
y' = (dx + ey + f) / w' ,
with w' = (gx + hy + i) .
Typically, a and e corresponds to the scaling on the X and Y
axes, c and f corresponds to the translation on those axes, and
g, h, and i are respectively 0, 0 and 1. The matrix can also be
used to express more complex transformations such as keystone
correction, or rotation. For a rotation of an angle T, this
formula can be used:
cos T -sin T 0
sin T cos T 0
0 0 1
As a special argument, instead of passing a matrix, one can pass
the string none, in which case the default values are used (a
unit matrix without filter).
因此,如果我写“xrandr --output eDP --scale 1.5x1.5”,这将创建一个变换矩阵:
M =
1.5 0 0
0 1.5 0
0 0 1
我使用 * 表示点积,(x,y) 是一些坐标
所以这等于:
w' = (0x + 0y + 1) = 1
x' = (1.5x + 0y + 1) / w' = 1.5x
y' = (0x + 1.5y + 1) / w' = 1.5y
这需要从最后一个 x,y 坐标进行线性和相对变换!可是等等,如果根据文档,比例值 > 1 应该压缩输出,这似乎实际上是在扩展输出,因为 (x,y) 被乘以 1.5。
我正在使用两个显示器,如果这意味着什么的话,我什至没有了解它如何影响另一个显示器的屏幕空间
答案1
我试图帮助你 - 昨天我读了文档,但很难理解。
我在下面画了这幅画。
x'=x cos T + y -sin T + c | a b c
y'=x sin T + y cos T + f | d e f | g=0, h=0, i=1
x 和 y(以显示器上输出模式的像素为单位)
x' 和 y'(以图形缓冲区中屏幕图像的像素为单位)
我有一台显示器:例如角度 10 度,比例 1.2 -> cos 10 x 1.2 = 1.1818,sin 10 x 1.2 = 0.2084
xrandr --output "DVI-D-0" --transform 1.1818,-0.2084,0,0.2084,1.1818,0,0,0,1
之后调用 xrandr 的输出xrandr
Screen 0: minimum 8 x 8, current 2270 x 1677, maximum 32767 x 32767
DVI-D-0 connected primary 2176x930+0+0 (normal left inverted right x axis y axis) 531mm x 299mm
1920x1080 60.00*+
1680x1050 59.95
1600x1200 60.00
1440x900 59.89
1280x1024 75.02 60.02
1280x960 60.00
1152x864 75.00
1024x768 75.03 70.07 60.00
800x600 75.00 72.19 60.32 56.25
640x480 75.00 72.81 59.94
HDMI-0 disconnected (normal left inverted right x axis y axis)
DP-0 disconnected (normal left inverted right x axis y axis)
DP-1 disconnected (normal left inverted right x axis y axis)
2176x930 必须是图形缓冲区中的图像
(2176 x cos 10 + 930 x sin 10) / 1.2 = 1920
但我不确定画中的屏幕(黄色)!
缓冲区顶部像素中的图像到显示器屏幕底部之间的距离为:
2176 x sin 10 + 1080 x 1,2=1674,
但这包括空白显示器,但如果图像超出显示器,我敢打赌这幅画是正确的。
您可以通过以下方式返回到旧设置:
xrandr --output "DVI-D-0" --transform 1,0,0,0,1,0,0,0,1
保存您打开的每个文件,有两次我崩溃了,我的显示器没有信号,因为输入错误,不得不重新启动!