如标题所述。
\documentclass{article}
\usepackage{algorithm}
% Need it for floating environment
\usepackage[noend]{algpseudocode}
% Hide endif .etc
\usepackage{caption}
% Need it for \caption*
\usepackage{xspace}
% Fix macro spacing bug
\algrenewcommand{\algorithmicrequire}{\textbf{Input:}}
\algrenewcommand{\algorithmicensure}{\textbf{Output:}}
\algrenewcommand{\algorithmicforall}{\textbf{for each}}
% \algrenewcommand instead of \renewcommand according to manual
\newcommand{\To}{\textbf{to}\xspace}
% Not stated in manual, \Return and \algorithmicreturn are defined, but no \algorithmicstate, why?
\newcommand{\Dosth}{\State \textbf{Do Something}\xspace}
% Note no space before \xspace
\newcommand{\Please}[1]{\State \textbf{#1}}
\newcommand{\ForEach}{\ForAll}
% Fail to use \algorithmicforall, why?
\begin{document}
\begin{algorithm}
\caption*{\textbf{Algorithm:} \textsc{Depth First Search}} \label{alg:dfs1}
\begin{algorithmic}[1]
\Function{DFS}{$v$}
\State $count \gets count + 1$
\Please{mark} $v$ with $count$
\Dosth with $v$
\ForEach{vertex $w \in \mathcal{V}$ adjacent to $v$}
\If{$w$ is marked with $0$} \Comment Only needed to exclude its parent.\footnotemark
\State \Call{DFS}{$w$}
\EndIf
\EndFor
\State \Return
\EndFunction
\end{algorithmic}
\end{algorithm}
\footnotetext{No sibling is visited before the loop. Each sibling will be visited exactly once due to the nature of the loop.}
\end{document}
答案1
一种选择是使用H
位置说明符(由algorithm
包通过包提供float
),从而允许将环境包含algorithm
在内minipage
(当然,algorithm
不会再浮动);现在,\footnote
可以使用标准命令来放置脚注。
\documentclass{article}
\usepackage{algorithm}
% Need it for floating environment
\usepackage[noend]{algpseudocode}
% Hide endif .etc
\usepackage{caption}
% Need it for \caption*
\usepackage{xspace}
% Fix macro spacing bug
\algrenewcommand{\algorithmicrequire}{\textbf{Input:}}
\algrenewcommand{\algorithmicensure}{\textbf{Output:}}
\algrenewcommand{\algorithmicforall}{\textbf{for each}}
% \algrenewcommand instead of \renewcommand according to manual
\newcommand{\To}{\textbf{to}\xspace}
% Not stated in manual, \Return and \algorithmicreturn are defined, but no \algorithmicstate, why?
\newcommand{\Dosth}{\State \textbf{Do Something}\xspace}
% Note no space before \xspace
\newcommand{\Please}[1]{\State \textbf{#1}}
\newcommand{\ForEach}{\ForAll}
% Fail to use \algorithmicforall, why?
\begin{document}
\noindent\begin{minipage}{\textwidth}
\begin{algorithm}[H]
\caption*{\textbf{Algorithm:} \textsc{Depth First Search}} \label{alg:dfs1}
\begin{algorithmic}[1]
\Function{DFS}{$v$}
\State $count \gets count + 1$
\Please{mark} $v$ with $count$
\Dosth with $v$
\ForEach{vertex $w \in \mathcal{V}$ adjacent to $v$}
\If{$w$ is marked with $0$} \Comment Only needed to exclude its parent.\footnote{No sibling is visited before the loop. Each sibling will be visited exactly once due to the nature of the loop.}
\State \Call{DFS}{$w$}
\EndIf
\EndFor
\State \Return
\EndFunction
\end{algorithmic}
\end{algorithm}
\renewcommand\footnoterule{}
\end{minipage}
\end{document}
编辑:最初我明确加载了float
包以使用H
说明符;这不是必需的,因为algorithm
内部使用float
。
EDIT2:没有必要使用\mpfootnotemark
;标准\footnote
命令可以在里面使用minipage
。