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如何在不使用嵌套表的情况下使跨多行的内容垂直居中？

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如何在不使用嵌套表的情况下使跨多行的内容垂直居中？

我不想使用嵌套表。我当前的代码产生以下结果。

在此处输入图片描述

我想要获得以下输出。

在此处输入图片描述

最小工作示例：

\documentclass{article}
\usepackage[a4paper,margin=1cm,showframe]{geometry}
\usepackage{array,multirow,longtable}

\parindent=0pt
\arrayrulewidth=1pt\relax
\tabcolsep=5pt\relax

\newcolumntype{A}[2]{%
    >{\minipage{\dimexpr#1\linewidth-2\tabcolsep-#2\arrayrulewidth\relax}\vspace\tabcolsep}%
    c<{\vspace\tabcolsep\endminipage}}


\newcommand\x{\centering$\displaystyle\int f(x)\,\textrm{d}x=F(x)+C$}

\begin{document}
\begin{longtable}{
            |A{0.2}{1.5}    % 0.2 of \linewidth, 1.5 of \arrayrulewidth
            |A{0.5}{1}      % 0.5 of \linewidth, 1 of \arrayrulewidth
            |A{0.3}{1.5}    % 0.3 of \linewidth, 1.5 of \arrayrulewidth
            |}\hline
%%%%%%%%%%%%%%% FIRST ROW %%%%%%%%%%%%%%% 
\x & \multicolumn{2}{
                A{0.8}{1.5} % 0.8 of \linewidth, 1.5 of \arrayrulewidth
                |}{\x} \tabularnewline\hline
%%%%%%%%%%%%%%% SECOND ROW %%%%%%%%%%%%%%%
\multicolumn{2}{
        |A{0.7}{1.5}    % 0.7 of \linewidth, 1.5 of \arrayrulewidth
        |}{\multirow{2}{*}{\x}} &
                                                        \x \tabularnewline\cline{3-3}
%%%%%%%%%%%%%%% THIRD ROW %%%%%%%%%%%%%%%
\multicolumn{2}{
        |A{0.7}{1.5}    % 0.7 of \linewdith, 1.5 of \arrayrulewidth
        |}{}                    & 
                                                        \x \tabularnewline\hline
\end{longtable}
\end{document}

如何在不使用嵌套表的情况下使跨多行的内容垂直居中？

我尝试了所有答案（Aditya 的答案除外），但都没有将跨多行的单元格垂直居中。请重新检查您的答案，否则我可能错了。:-)

答案1

该软件包ltablex可在 CTAN 上获得：http://www.ctan.org/tex-archive/macros/latex/contrib/ltablex 当您想要不同的列宽时，三个 X 列必须给出 3X：0.6+1.5+0.9=3 对于第二行和第三行，您有 2X+1X=3X

\documentclass{article}
\usepackage[a4paper,margin=1cm,showframe]{geometry}
\usepackage{multirow,bigstrut,ltablex,calc}
\parindent=0pt
\tabcolsep=5pt
\newcolumntype{A}[1]{>{\hsize=#1\hsize\rule{0pt}{\tabcolsep}\newline}
                      X
                     <{\newline\rule[-\tabcolsep]{0pt}{\tabcolsep}}}

\newcommand\x{\makebox[\hsize]{$\displaystyle\int f(x)\,\textrm{d}x=F(x)+C$}}

\begin{document}

\keepXColumns
\begin{tabularx}{\linewidth}{| A{0.6} | A{1.5} | A{0.9} |}\hline
\x & \multicolumn{2}{A{2.4}|}{\x} \tabularnewline\hline
%%%%%%%%%%%%%%% SECOND ROW %%%%%%%%%%%%%%%
\multicolumn{2}{|A{2}|}{\multirow{4}[8]{*}{\x}} &  \x\tabularnewline\cline{3-3}
%%%%%%%%%%%%%%% THIRD ROW %%%%%%%%%%%%%%%
\multicolumn{2}{|A{2}|}{}                       &  \x \tabularnewline\hline
\end{tabularx}

\end{document}

在此处输入图片描述

答案2

您可以通过对原始代码进行简单修改来获得所需的结果，将第二行替换\multirow{2}{*}{\x}为：\hfil\multirow{4}{*}{\x}\hfil

\documentclass{article}
\usepackage[a4paper,margin=1cm,showframe]{geometry}
\usepackage{array,multirow,longtable}

\parindent=0pt
\arrayrulewidth=1pt\relax
\tabcolsep=5pt\relax

\newcolumntype{A}[2]{%
    >{\minipage{\dimexpr#1\linewidth-2\tabcolsep-#2\arrayrulewidth\relax}\vspace\tabcolsep}%
    c<{\vspace\tabcolsep\endminipage}}


\newcommand\x{\centering$\displaystyle\int f(x)\,\textrm{d}x=F(x)+C$}

\begin{document}
\begin{longtable}{
            |A{0.2}{1.5}    % 0.2 of \linewidth, 1.5 of \arrayrulewidth
            |A{0.5}{1}      % 0.5 of \linewidth, 1 of \arrayrulewidth
            |A{0.3}{1.5}    % 0.3 of \linewidth, 1.5 of \arrayrulewidth
            |}\hline
%%%%%%%%%%%%%%% FIRST ROW %%%%%%%%%%%%%%% 
\x & \multicolumn{2}{
                A{0.8}{1.5} % 0.8 of \linewidth, 1.5 of \arrayrulewidth
                |}{\x} \tabularnewline\hline
%%%%%%%%%%%%%%% SECOND ROW %%%%%%%%%%%%%%%
\multicolumn{2}{
        |A{0.7}{1.5}    % 0.7 of \linewidth, 1.5 of \arrayrulewidth
        |}{\hfil\multirow{4}{*}{\x}\hfil} & \x \tabularnewline\cline{3-3}
%%%%%%%%%%%%%%% THIRD ROW %%%%%%%%%%%%%%%
\multicolumn{2}{
        |A{0.7}{1.5}    % 0.7 of \linewdith, 1.5 of \arrayrulewidth
        |}{}  & \x \tabularnewline\hline
\end{longtable}

\end{document}

在此处输入图片描述

答案3

对于排版这样的表格，我发现 ConTeXt 提供的界面更易于阅读。

\startsetups table:setup
  \setupTABLE[each][each][align={middle,middle}, frame=on, framecolor=red]
  \setupTABLE[column][1] [width=0.2\hsize]
  \setupTABLE[column][2] [width=0.5\hsize]
  \setupTABLE[column][3] [width=0.3\hsize]
\stopsetups

\startbuffer
$\displaystyle \int f(x)\,\normal{d}x=F(x)+C$
\stopbuffer

\starttext

  \bTABLE[setups=table:setup]
    \bTR
      \bTD \getbuffer \eTD \bTD[nc=2] \getbuffer \eTD 
    \eTR
    \bTR
      \bTD[nc=2, nr=2] \getbuffer \eTD \bTD \getbuffer \eTD 
    \eTR
    \bTR
       \bTD \getbuffer \eTD 
    \eTR
  \eTABLE
\stoptext

这给出

在此处输入图片描述

答案4

我提出的解决方案省去了minipages明确的\vspace指令。这是通过在每行中自动插入一个“支柱”来实现的；支柱的高度比数学表达式的高度高出一定量。

\documentclass{article}
\usepackage[a4paper,margin=1cm,showframe]{geometry}
\usepackage{array,multirow,tabularx}

\parindent=0pt
\arrayrulewidth=1pt
\tabcolsep=5pt

%% 'rbstrut' is short for 'really big strut'
\newcommand{\rbstrut}{\ensuremath{\vphantom{\displaystyle \int\limits_a^t}}}

\newcolumntype{A}[1]{>{\hsize=#1\hsize \centering \arraybackslash\rbstrut}X}

\newcommand\x{\ensuremath{\displaystyle\int f(x)\,\textrm{d}x=F(x)+C}}

\begin{document}

%% in tabularx terminology, the sum of the widths (arguments of A) have to
%% add up to the integer (in this case 3) that equals the number of columsn
\begin{tabularx}{\textwidth}{| A{0.6} | A{1.5} | A{0.9} |}
\hline
%%%% FIRST ROW 
\x & \multicolumn{2}{c|}{\x} \\    \hline
%%%% SECOND ROW 
\multicolumn{2}{|A{2.1}|}{ \multirow{4}{*}{\x} } & \x \\    \cline{3-3}
%%%% THIRD ROW
\multicolumn{2}{|c|}{}  &  \x \\    \hline
\end{tabularx}
\end{document}

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