我正在尝试使用环境绘制一些流程图psmatrix，并且必须在平行四边形框中显示我的输入和输出。当我的流程图中有平行四边形时，节点没有问题，但每当我尝试绘制水平节点时，我都会遇到下图中的问题，其中节点的一部分位于平行四边形内
\documentclass{article}
\usepackage{amsmath,amssymb}
\usepackage{pstricks}
\usepackage{pst-node}
\usepackage{pst-blur}
\definecolor{Blue}{rgb}{1.,0.75,0.8}
% ================================
% Source: http://tug.org/pipermail/pstricks/2009/006766.html
\makeatletter
\newdimen\psparallelogramsep
\def\psset@parallelogramsep#1{\pssetlength\psparallelogramsep{#1}}
\psset@parallelogramsep{3mm}
\def\psparallelogrambox{\pst@object{psparallelogrambox}}
\def\psparallelogrambox@i{\pst@makebox\psparallelogrambox@ii}
\def\psparallelogrambox@ii{%
\begingroup
\pst@useboxpar
\pst@dima=\pslinewidth
\advance\pst@dima by \psframesep
\pst@dimc=\wd\pst@hbox\advance\pst@dimc by \pst@dima
\pst@dimb=\dp\pst@hbox\advance\pst@dimb by \pst@dima
\pst@dimd=\ht\pst@hbox\advance\pst@dimd by \pst@dima
\setbox\pst@hbox=\hbox{%
\ifpsboxsep\kern\pst@dima\fi
\begin@ClosedObj
\addto@pscode{%
\psk@cornersize
\pst@number\pst@dima neg
\pst@number\pst@dimb neg
\pst@number\pst@dimc
\pst@number\pst@dimd .5
\pst@number\psparallelogramsep
\tx@Parallelogram}%
\def\pst@linetype{2}%
\showpointsfalse
\end@ClosedObj
\box\pst@hbox
\ifpsboxsep\kern\pst@dima\fi%
}%
\ifpsboxsep\dp\pst@hbox=\pst@dimb\ht\pst@hbox=\pst@dimd\fi
\leavevmode\box\pst@hbox
\endgroup%
}
% From the Frame and Rect PostScript macros
\pst@def{Parallelogram}<{%
/ParallelogramA {
x1 pgs sub y1 moveto
x1 y2 lineto
x2 pgs add y2 lineto
x2 y1 lineto
x1 pgs sub y1 lineto
closepath} def
%
/pgs ED
CLW mul
/a ED
3 -1 roll
2 copy gt { exch } if
a sub
/y2 ED
a add
/y1 ED
2 copy gt { exch } if
a sub
/x2 ED
a add
/x1 ED
1 index 0 eq {pop pop ParallelogramA } { OvalFrame } ifelse}>
\makeatother
\def\pspbox[#1]#2{\makebox[#1]{\psparallelogrambox{#2}}}
% ================================
\pagestyle{empty}
\begin{document}
\begin{latin}
\vspace{0.5cm}
\small
\psset{shadowcolor=black!70,shadowangle=-90,blur=true}
\begin{psmatrix}[rowsep=0.7,colsep=0.7]% defines the distance between two frames
%Begin
\psovalbox[fillstyle=solid, fillcolor=yellow!30,shadow=true]{Start} \\
%input
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20,shadow=true]{Input r} \\
%Condition
\psdiabox[fillstyle=solid, fillcolor=magenta!20,shadow=true]{$ r > 0 $} &
%output
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20,shadow=true]{Print m , d , s} \\
%computation
\psframebox[shadow=true]{$ d=2*r $} &
%End
\psovalbox[fillstyle=solid, fillcolor=yellow!30,shadow=true]{End}\\
%computation
\psframebox[shadow=true]{$ m=2*\pi*r $} \\
%computation
\psframebox[shadow=true]{$ s = \pi*r*r $} \\
%output
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20, shadow=true]{Print Sum} \\
% Links
\ncline{->}{1,1}{2,1}
\ncline{->}{2,1}{3,1}
\ncline{->}{3,1}{4,1}<{\textcolor{red}{Yes}}
\ncline{->}{4,1}{5,1}
\ncline{->}{5,1}{6,1}
\ncline{->}{6,1}{7,1}
\ncline{->}{3,1}{3,2}^{\textcolor{red}{No}}
\ncline{->}{3,2}{4,2}
\ncangles[angleA=-90,angleB=180,armA=0.5cm,armB=0.7cm]{->}{7,1}{3,1}
\end{psmatrix}
\end{document}
那么我应该怎么做才能获得正确的节点？
答案1
使用来自的包pstricks-add（v. 3.57）http://texnik.dante.de/tex/generic/pstricks-add/
它知道具有更好代码的命令\psparallelogrambox。您的示例可以是：
\documentclass{article}
\usepackage{amsmath,amssymb}
\usepackage{pst-blur}
\usepackage{pstricks-add}
\definecolor{Blue}{rgb}{1.,0.75,0.8}
\pagestyle{empty}
\begin{document}
\psset{shadowcolor=black!70,shadowangle=-90,blur,shortput=nab}
\begin{psmatrix}[rowsep=0.7,colsep=0.7]
\psovalbox[fillstyle=solid, fillcolor=yellow!30,shadow=true]{Start} \\
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20,shadow]{Input r} \\
\psdiabox[fillstyle=solid, fillcolor=magenta!20,shadow=true]{$ r > 0 $} &
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20,shadow=true]{Print m, d, s} \\
\psframebox[shadow=true]{$ d=2*r $} &
\psovalbox[fillstyle=solid, fillcolor=yellow!30,shadow=true]{End}\\
\psframebox[shadow=true]{$ m=2*\pi*r $} \\
\psframebox[shadow=true]{$ s=\pi*r*r $} \\
\psparallelogrambox[fillstyle=solid,fillcolor=blue!20, shadow=true]{Print Sum}
\end{psmatrix}
\ncline{->}{1,1}{2,1}\ncline{->}{2,1}{3,1}
\ncline{->}{3,1}{4,1}_{\textcolor{red}{Yes}}
\ncline{->}{4,1}{5,1}\ncline{->}{5,1}{6,1}
\ncline{->}{6,1}{7,1}
\ncline{->}{3,1}{3,2}^{\textcolor{red}{No}}
\ncline{->}{3,2}{4,2}
\ncangles[angleA=-90,angleB=180,armA=0.5cm,armB=0.7cm]{->}{7,1}{3,1}
\end{document}
