大小分隔符 (\left( \right)) 对于垂直对齐数组 (\begin{array}[t]) 来说太高

Question

请编译下面的内容，问题就会清楚。

\documentclass{article}
\begin{document}
\noindent Compare
\[
\begin{array}{l}
  \land ~a\\
  \land \left(
    \begin{array}[t]{l}
      \lor ~a\\
      \lor \left(
        \begin{array}[t]{l}
          \land ~a\\
          \land ~b\\
        \end{array}
      \right)
    \end{array}
  \right)\\
\end{array}
\]
with
\[
\begin{array}{l}
  \land ~a\\
  \land
    \begin{array}[t]{l}
      \lor ~a\\
      \lor
        \begin{array}[t]{l}
          \land ~a\\
          \land ~b\\
        \end{array}
    \end{array}
\end{array}
.\]
I also don't want
\[
\begin{array}{l}
  \land ~a\\
  \land \left(
    \begin{array}{l}
      \lor ~a\\
      \lor \left(
        \begin{array}{l}
          \land ~a\\
          \land ~b\\
        \end{array}
      \right)
    \end{array}
  \right)\\
\end{array}
,\]
although it's better than the first version.
\end{document}

我想要第二个版本中的垂直布局，但嵌套子公式周围有括号。

Answer 1

这是相当接近的，间距可以稍微调整一下，取决于您的需要，这只是包中的默认间距。

\documentclass{article}
\usepackage{delarray}
\begin{document}
\noindent Compare
\[
\begin{array}{ll}
  \land &a\\
  \land&\begin{array}[t]({ll})
           \lor &a\\
            \lor &
           \begin{array}[t]({ll})
              \land&a\\
               \land&b
           \end{array}
\end{array}
\end{array}
\]

\end{document}