我有一个二项式树，箭头指向后方。目前，我有一些指向最左侧节点（不可见）的短箭头。第一列占用的视觉空间很小，但它将我的tikz格子向右推了整整一列的宽度。
怎么修？
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{matrix,fit,backgrounds}
\begin{document}
\begin{tikzpicture}[>=stealth,sloped]
\matrix (tree) [%
matrix of nodes,
minimum size=1cm,
column sep=2.7cm,
row sep=0.4cm,
column 4/.style={nodes={draw,fill=cyan!30,rounded corners}},
]
{
& & & $^\tau S_0$ \\
& & $R^{-1}(p (_\tau S_0) + (1-p) (_\tau S_2))$ & \\
& ... & & $^\tau S_1$ \\
$ $ & & $R^{-1}(p (_\tau S_1) + (1-p) (_\tau S_2))$ & \\
& ... & & $^\tau S_2$ \\
& & $R^{-1}(p (_\tau S_2) + (1-p) (_\tau S_3))$ & \\
& & & $^\tau S_3$ \\
};
\draw[<-,shorten <=2cm,double,double distance=1pt] (tree-4-1) -- (tree-3-2) node [midway,above] {};
\draw[<-,shorten <=2cm,double,double distance=1pt] (tree-4-1) -- (tree-5-2) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-3-2) -- (tree-2-3) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-3-2) -- (tree-4-3) node [midway,below] {};
\draw[<-,double,double distance=1pt] (tree-5-2) -- (tree-4-3) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-5-2) -- (tree-6-3) node [midway,below] {};
\draw[<-,double,double distance=1pt] (tree-2-3) -- (tree-1-4) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-2-3) -- (tree-3-4) node [midway,below] {};
\draw[<-,double,double distance=1pt] (tree-4-3) -- (tree-3-4) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-4-3) -- (tree-5-4) node [midway,below] {};
\draw[<-,double,double distance=1pt] (tree-6-3) -- (tree-5-4) node [midway,above] {};
\draw[<-,double,double distance=1pt] (tree-6-3) -- (tree-7-4) node [midway,below] {};
\end{tikzpicture}
\end{document}
答案1
您的column sep选项对第一列也有效。因此您需要覆盖它。此外，如果您的所有节点都涉及数学运算符，您可以简单地使用，matrix of math nodes这样您就不需要$对条目使用符号了。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{matrix,fit,backgrounds}
\begin{document}
\begin{tikzpicture}[>=stealth,sloped,mypath/.style={<-,double,double distance=1pt}]
\matrix (tree) [%
matrix of nodes,
minimum size=1cm,
column sep=2.7cm,
row sep=0.4cm,
column 4/.style={nodes={draw,fill=cyan!30,rounded corners}},
column 1/.style={nodes={minimum size=3mm,inner sep=1pt,outer sep=0},column sep=3mm},
]
{
& & &$^\tau S_0$ \\
& & $R^{-1}(p (_\tau S_0) + (1-p) (_\tau S_2))$ & \\
& ... & & $^\tau S_1$ \\
$ $ & & $R^{-1}(p (_\tau S_1) + (1-p) (_\tau S_2))$ & \\
& ... & & $^\tau S_2$ \\
& & $R^{-1}(p (_\tau S_2) + (1-p) (_\tau S_3))$ & \\
& & & $^\tau S_3$ \\
};
\draw[mypath,shorten <=2mm] (tree-4-1) -- (tree-3-2) node [midway,above] {};
\draw[mypath,shorten <=2mm] (tree-4-1) -- (tree-5-2) node [midway,above] {};
\draw[mypath] (tree-3-2) -- (tree-2-3) node [midway,above] {};
\draw[mypath] (tree-3-2) -- (tree-4-3) node [midway,below] {};
\draw[mypath] (tree-5-2) -- (tree-4-3) node [midway,above] {};
\draw[mypath] (tree-5-2) -- (tree-6-3) node [midway,below] {};
\draw[mypath] (tree-2-3) -- (tree-1-4) node [midway,above] {};
\draw[mypath] (tree-2-3) -- (tree-3-4) node [midway,below] {};
\draw[mypath] (tree-4-3) -- (tree-3-4) node [midway,above] {};
\draw[mypath] (tree-4-3) -- (tree-5-4) node [midway,below] {};
\draw[mypath] (tree-6-3) -- (tree-5-4) node [midway,above] {};
\draw[mypath] (tree-6-3) -- (tree-7-4) node [midway,below] {};
\end{tikzpicture}
\end{document}
