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方程式中的点符号

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方程式中的点符号

我正在用 LaTeX 写一个数学方程，但想用虚线段表示一些符号。实际上，我想使用\sqcup由三条线段组成的，并希望每条线段都用虚线代替。有人能告诉我怎么做吗？

答案1

它是TikZ 解决方案。

代码

\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usetikzlibrary{calc}

\newcommand*\Dottedsqcupmaxdots{7}
\newcommand*\Dottedsqcupcircleradius{.7\pgflinewidth}
\newcommand*\DottedSqCupsquarefactor{1.8}
\newcommand*\everyscquphspace{\mspace{1.2mu}} % needs amsmath

\newbox\boxdottedsqcup
\newbox\boxDottedsqcup
\newbox\boxDottedSqcup
\newbox\boxDottedSqCup

\savebox\boxdottedsqcup{\ensuremath{\everyscquphspace}\tikz{\draw[dash pattern=on \pgflinewidth off \pgflinewidth] (0,14.5\pgflinewidth) -- (0,0) -- (12\pgflinewidth,0) -- + (0,14.5\pgflinewidth);}\ensuremath{\everyscquphspace}}
\savebox\boxDottedsqcup{%
    \ensuremath{\everyscquphspace}%
    \tikz{
        \foreach \x in {0,...,\Dottedsqcupmaxdots} {
            \fill (0,2*\x*\pgflinewidth) circle (\Dottedsqcupcircleradius);
            \ifnum\x<\numexpr\Dottedsqcupmaxdots-1\relax
                \fill (2*\x*\pgflinewidth,0) circle (\Dottedsqcupcircleradius);
            \fi
            \pgfmathparse{2*(\Dottedsqcupmaxdots-1)*\pgflinewidth}
            \fill (\pgfmathresult pt,2*\x*\pgflinewidth) circle (\Dottedsqcupcircleradius);
        }
    }%
    \ensuremath{\everyscquphspace}%
}
\savebox\boxDottedSqcup{%
\ensuremath{\everyscquphspace}%
    \tikz{
    \pgfmathparse{\Dottedsqcupmaxdots-1}
        \foreach \x in {0,...,\pgfmathresult} {
            \fill (0,2.2*\x*\pgflinewidth) circle (\Dottedsqcupcircleradius);
%           \ifnum\x<\numexpr\Dottedsqcupmaxdots-1\relax
                \fill (2.2*\x*\pgflinewidth,0) circle (\Dottedsqcupcircleradius);
%           \fi
            \pgfmathparse{2.2*(\Dottedsqcupmaxdots-1)*\pgflinewidth}
            \fill (\pgfmathresult pt,2.2*\x*\pgflinewidth) circle (\Dottedsqcupcircleradius);
        }
    }%
    \ensuremath{\everyscquphspace}%
}
\savebox\boxDottedSqCup{%
    \ensuremath{\everyscquphspace}%
    \tikz{
    \pgfmathparse{\Dottedsqcupmaxdots-1}
        \foreach \x in {0,...,\pgfmathresult} {
            \fill (0,2.2*\x*\pgflinewidth) ++(135:\Dottedsqcupcircleradius) rectangle +(\DottedSqCupsquarefactor*\Dottedsqcupcircleradius,-\DottedSqCupsquarefactor*\Dottedsqcupcircleradius);
%           \ifnum\x<\numexpr\Dottedsqcupmaxdots-1\relax
                \fill (2.2*\x*\pgflinewidth,0) ++(135:\Dottedsqcupcircleradius) rectangle +(\DottedSqCupsquarefactor*\Dottedsqcupcircleradius,-\DottedSqCupsquarefactor*\Dottedsqcupcircleradius);
%           \fi
            \pgfmathparse{2.2*(\Dottedsqcupmaxdots-1)*\pgflinewidth}
            \fill (\pgfmathresult pt,2.2*\x*\pgflinewidth) ++(135:\Dottedsqcupcircleradius) rectangle +(\DottedSqCupsquarefactor*\Dottedsqcupcircleradius,-\DottedSqCupsquarefactor*\Dottedsqcupcircleradius);
        }
    }%
    \ensuremath{\everyscquphspace}%
}

\newcommand*{\dottedsqcup}{\mathbin{\usebox\boxdottedsqcup}}
\newcommand*{\Dottedsqcup}{\mathbin{\usebox\boxDottedsqcup}}
\newcommand*{\DottedSqcup}{\mathbin{\usebox\boxDottedSqcup}}
\newcommand*{\DottedSqCup}{\mathbin{\usebox\boxDottedSqCup}}

\begin{document}\noindent
\(1\sqcup2\)\\
\(1\dottedsqcup 2\)\\
\(1\Dottedsqcup 2\)\\
\(1\DottedSqcup 2\)\\
\(1\DottedSqCup 2\)
\end{document}

输出

在此处输入图片描述

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