两个多列的中心对齐

Question

我要将 10e-1 和 10e-3 置于 4 个多列的中心。我该怎么做？

\usepackage{siunitx}
\usepackage{multirow}
\usepackage{booktabs}


\begin{table}[htp]
    \centering
    \begin{tabular}{lS[table-format=1.4]
                     S[table-format=1.4]
                     S[table-format=1.4]
                     S[table-format=1.4]}
        \toprule
            {\emph{Nodi}} & \multicolumn{4}{c}{PEP} \\
            \cmidrule(lr){2-5}
                        & \num{10e-1} &     &       & \num{10e-3} \\
            \cmidrule(lr){2-5}
                        & {BC}   & {PNC}    & {BC} & {PNC} \\
        \midrule
        1               & 1.1107 & 1.1112  & 1.001  & 1.001 \\
        3               & 1.3046 & 1.1488  & 1.003  & 1.0029 \\
        7               & 1.597  & 1.1734  & 1.007  & 1.006 \\
        12              & 1.8435 & 1.188   & 1.0117 & 1.0089 \\
        20              & 2.0836 & 1.2009  & 1.0201 & 1.0122 \\
        25              & 2.1777 & 1.2064  & 1.0246 & 1.0134 \\
        35              & 2.3101 & 1.2141  & 1.0347 & 1.0153 \\
        50              & 2.4443 & 1.2223  & 1.0488 & 1.0167 \\
        65              & 2.5501 & 1.228   & 1.0636 & 1.0175 \\
        75              & 2.6109 & 1.2308  & 1.0723 & 1.0178 \\
        90              & 2.6915 & 1.235   & 1.0864 & 1.0184 \\
        100             & 2.7417 & 1.237   & 1.0954 & 1.0186 \\
        \bottomrule
    \end{tabular}
\end{table}

Answer 1

为了使两个元素在四列中居中，只需将它们视为一个\multicolumn元素：

& \multicolumn{4}{c}{\num{10e-1}\quad\num{10e-3}} \\ 

代码：

\documentclass{article}
\usepackage{siunitx}
\usepackage{booktabs}

\begin{document}
\begin{table}[htp]
    \centering
    \begin{tabular}{lS[table-format=1.4]
                     S[table-format=1.4]
                     S[table-format=1.4]
                     S[table-format=1.4]}
        \toprule
            {\emph{Nodi}} & \multicolumn{4}{c}{PEP} \\
            \cmidrule(lr){2-5}
                        & \multicolumn{4}{c}{\num{10e-1}\quad\num{10e-3}}  \\
            \cmidrule(lr){2-5}
                        & {BC}   & {PNC}    & {BC} & {PNC} \\
        \midrule
        1               & 1.1107 & 1.1112  & 1.001  & 1.001 \\
        3               & 1.3046 & 1.1488  & 1.003  & 1.0029 \\
        7               & 1.597  & 1.1734  & 1.007  & 1.006 \\
        12              & 1.8435 & 1.188   & 1.0117 & 1.0089 \\
        20              & 2.0836 & 1.2009  & 1.0201 & 1.0122 \\
        25              & 2.1777 & 1.2064  & 1.0246 & 1.0134 \\
        35              & 2.3101 & 1.2141  & 1.0347 & 1.0153 \\
        50              & 2.4443 & 1.2223  & 1.0488 & 1.0167 \\
        65              & 2.5501 & 1.228   & 1.0636 & 1.0175 \\
        75              & 2.6109 & 1.2308  & 1.0723 & 1.0178 \\
        90              & 2.6915 & 1.235   & 1.0864 & 1.0184 \\
        100             & 2.7417 & 1.237   & 1.0954 & 1.0186 \\
        \bottomrule
    \end{tabular}
\end{table}
\end{document}