我想创建工作表，其中的问题按行而不是列填充。我用它probsoln来存储和调用问题，但它们总是垂直填满工作表。我尝试将它们放在表格中，但我无法让它工作。
\documentclass[letter]{article}
\usepackage{probsoln}
\usepackage{amsmath}
\usepackage{multicol}
\PSNrandseed{2004}
\hideanswers
\begin{document}
\ifthenelse{\boolean{showanswers}}{\textbf{Solution Sheet}}{}
\loadrandomproblems{10}{AddingFractionsDatabase}
\begin{tabular}{lllll}
\foreachproblem{\thisproblem\\}%
\end{tabular}
\end{document}
我希望能够根据需要从每个文件中提取一两行问题。如果可能的话，我想使用考试类。
测试数据库
\newproblem{addfractions:1212}
{$\frac{1}{2} + \frac{1}{2} = $}
{$\frac{1}{2} + \frac{1}{2} = \frac{2}{2} = 1$}
\newproblem{addfractions:1213}
{$\frac{1}{2} + \frac{1}{3} = $}
{$\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$}
\newproblem{addfractions:1223}
{$\frac{1}{2} + \frac{2}{3} = $}
{$\frac{1}{2} + \frac{2}{3} = \frac{3}{6} + \frac{4}{6} = \frac{7}{6} = 1 \frac{1}{6}$}
\newproblem{addfractions:1214}
{$\frac{1}{2} + \frac{1}{4} = $}
{$\frac{1}{2} + \frac{1}{4} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4}$}
\newproblem{addfractions:1216}
{$\frac{1}{2} + \frac{1}{6} = $}
{$\frac{1}{2} + \frac{1}{6} = \frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$}
\newproblem{addfractions:1256}
{$\frac{1}{2} + \frac{5}{6} = $}
{$\frac{1}{2} + \frac{5}{6} = \frac{3}{6} + \frac{5}{6} = \frac{8}{6} = 1 \frac{2}{6} = 1 \frac{1}{3}$}
\newproblem{addfractions:1217}
{$\frac{1}{2} + \frac{1}{7} = $}
{$\frac{1}{2} + \frac{1}{7} = \frac{7}{14} + \frac{2}{14} = \frac{9}{14}$}
\newproblem{addfractions:1227}
{$\frac{1}{2} + \frac{2}{7} = $}
{$\frac{1}{2} + \frac{2}{7} = \frac{7}{14} + \frac{4}{14} = \frac{11}{14}$}
\newproblem{addfractions:1237}
{$\frac{1}{2} + \frac{3}{7} = $}
{$\frac{1}{2} + \frac{3}{7} = \frac{7}{14} + \frac{6}{14} = \frac{13}{14}$}
\newproblem{addfractions:1247}
{$\frac{1}{2} + \frac{4}{7} = $}
{$\frac{1}{2} + \frac{4}{7} = \frac{7}{14} + \frac{8}{14} = \frac{15}{14} = 1 \frac{1}{14}$}
\newproblem{addfractions:1257}
{$\frac{1}{2} + \frac{5}{7} = $}
{$\frac{1}{2} + \frac{5}{7} = \frac{7}{14} + \frac{10}{14} = \frac{17}{14} = 1 \frac{3}{14}$}
\newproblem{addfractions:1267}
{$\frac{1}{2} + \frac{6}{7} = $}
{$\frac{1}{2} + \frac{6}{7} = \frac{7}{14} + \frac{12}{14} = \frac{19}{14} = 1 \frac{5}{14}$}
\newproblem{addfractions:1218}
{$\frac{1}{2} + \frac{1}{8} = $}
{$\frac{1}{2} + \frac{1}{8} = \frac{4}{8} + \frac{1}{8} = \frac{5}{8}$}
\newproblem{addfractions:1238}
{$\frac{1}{2} + \frac{3}{8}= $}
{$\frac{1}{2} + \frac{3}{8} = \frac{4}{8} + \frac{3}{8} = \frac{7}{8}$}
\newproblem{addfractions:1258}
{$\frac{1}{2} + \frac{5}{8}= $}
{$\frac{1}{2} + \frac{5}{8} = \frac{4}{8} + \frac{5}{8} = \frac{9}{8} = 1 \frac{1}{8}$}
\newproblem{addfractions:1278}
{$\frac{1}{2} + \frac{7}{8}= $}
{$\frac{1}{2} + \frac{7}{8} = \frac{4}{8} + \frac{7}{8} = \frac{11}{8} = 1 \frac{3}{8}$}
\newproblem{addfractions:1219}
{$\frac{1}{2} + \frac{1}{9}= $}
{$\frac{1}{2} + \frac{1}{9} = \frac{9}{18} + \frac{2}{18} = \frac{11}{18}$}
答案1
您可以通过跟踪您所在的列来实现这一点，如下所示：
\documentclass{article}
\usepackage{etoolbox}
\usepackage{probsoln}
\usepackage{amsmath}
\usepackage{multicol}
\PSNrandseed{2004}
\hideanswers
\begin{document}
\ifthenelse{\boolean{showanswers}}{\textbf{Solution Sheet}}{}
\loadrandomproblems{10}{AddingFractionsDatabase}
\newcounter{colcount}
\begin{tabular}{lllll}
\foreachproblem{\thisproblem
\global\stepcounter{colcount}%
\ifnumless{\value{colcount}}{4}{&}{\global\setcounter{colcount}{0}\\}%
}%
\end{tabular}
\end{document}
结果：
