谁能告诉我如何重写这些方程式:
有花括号和半行移位,我不知道如何在 align( eqnarray
) 环境中写入它。
答案1
我想,这已经足够接近了:
\documentclass{article}
\usepackage{array}% http://ctan.org/pkg/array
\newcommand{\vplus}{\begin{array}{l}\vphantom{+2=t_{1,1}}\\\vphantom{+2=t_{1,1}}\end{array}}
\begin{document}
\[
\setlength{\arraycolsep}{0pt}
\renewcommand{\arraystretch}{1.2}
\begin{array}{rl}
a_{ 1,2} & {}= 1 \\
a_{ 2,2} & {}= 5 \\
a_{ 3,2} & {}= 7 \\
a_{ 4,2} & {}= 11 \\
a_{ 5,2} & {}= 13 \\
a_{ 6,2} & {}= 17 \\
a_{ 7,2} & {}= 19 \\
a_{ 8,2} & {}= 23 \\
a_{ 9,2} & {}= 25 \\
a_{10,2} & {}= 29 \\
{}
\end{array} \quad \begin{array}{r>{\hphantom{\biggr\}}}l}
\multicolumn{2}{l}{\begin{array}{r}
+4 \\ +2
\end{array}\biggr\}\begin{array}{l}
{}= t_{1,2} \\ {}= t_{2,2}
\end{array}\smash{\biggr\}}} \\
+4 & {}= t_{1,2} \\
+2 & {}= t_{2,2} \\
+4 & {}= t_{1,2} \\
+2 & {}= t_{2,2} \\
+4 & {}= t_{1,2} \\
\multicolumn{2}{l}{\begin{array}{r}
+2 \\ +4
\end{array}\smash{\biggr\}}\begin{array}{l}
{}= t_{2,2} \\ {}= t_{1,2}
\end{array}\biggr\}} \\
+2 & {}= t_{2,2}
\end{array} \quad \begin{array}{l}
\vplus\begin{array}{rl}
6 & {}= t_{1,3}
\end{array} \\
\begin{array}{>{\phantom{6}}rl}
& {}= t_{2,3} \\
& {}= t_{3,3} \\
& {}= t_{4,3} \\
& {}= t_{5,3} \\
& {}= t_{6,3}
\end{array} \\
\vplus\begin{array}{rl}
6 & {}= t_{7,3} = t_{1,2} + t_{2,2}
\end{array} \\
\begin{array}{>{\phantom{6}}rl}
& {}= t_{8,3}
\end{array}
\end{array}
\]
\end{document}
array
这个解决方案受到围绕数学轴垂直居中这一事实的很大影响。