我正在尝试为仅在一周中的某些日子(M、W)上课的课程编写课程大纲。我想检查课程日期,并根据日期将其提前 2 天或 5 天。以下代码似乎不起作用(语句失败\ifthenelse
)
\documentclass{article}
\usepackage{advdate}
\usepackage[ddmmyyyy]{datetime}
\usepackage{tikz}
\newdateformat{syldate}{\THEMONTH/\THEDAY%(\shortdayofweekname%{\THEDAY}{\THEMONTH}{\THEYEAR})}
\newcommand{\class}[1]{
\def \currday {\shortdayofweekname{\the\day}{\the\month}{\the\year}}
\ifthenelse{\equal{\currday}{Mon}}{\AdvanceDate[2]}{\AdvanceDate[5]}
\section* {\syldate{\today} \quad #1}
}
\SetDate[06/01/2014]
\begin{document}
\class{First Class}
\class{Second class}
\class{Class after holiday}
\end{document}
我之所以要这样做,是因为我想检查是否\today
在假期列表中,如果是,则自动前进到下一个上课日。有什么建议吗?如果有更高效的代码就更好了。
答案1
希望这就是你所追求的:
\documentclass{article}
\usepackage[ddmmyyyy]{datetime}% http://ctan.org/pkg/datetime
\usepackage{advdate}% http://ctan.org/pkg/advdate
\newdateformat{syldate}{\THEMONTH/\THEDAY/\THEYEAR}%(\shortdayofweekname%{\THEDAY}{\THEMONTH}{\THEYEAR})}
\newsavebox{\MONDAY}\savebox{\MONDAY}{Mon}% Mon
\makeatletter
\newcommand{\cleardate}[1]{%
\expandafter\let\csname date@#1@d\endcsname\relax% Clear day
\expandafter\let\csname date@#1@m\endcsname\relax% Clear month
\expandafter\let\csname date@#1@y\endcsname\relax% Clear year
}
\makeatother
\newcommand{\class}[1]{%
\cleardate{mydate}% Clear date
\newdate{mydate}{\the\day}{\the\month}{\the\year}% Store date
\section*{\displaydate{mydate} \quad #1}% Set heading
\setbox1=\hbox{\shortdayofweekname{\getdateday{mydate}}{\getdatemonth{mydate}}{\getdateyear{mydate}}}%
\ifdim\wd1=\wd\MONDAY
\AdvanceDate[2]
\else
\AdvanceDate[5]
\fi%
}
\SetDate[06/01/2014]
\begin{document}
\class{First class}
\class{Second class}
\class{Third class}
\class{Fourth class}
\class{Fifth class}
\class{Sixth class}
\class{Seventh class}
\end{document}
该过程将数据存储在mydate
连接接口中datetime
和advdate
。通过测试单词的宽度来与星期几进行比较Mon
。每个三字母/短日期的长度不同: