流程图中仍缺少一些流程

流程图中仍缺少一些流程

几天前我已经发布了这个问题,但我仍然无法完成算法。

在此处输入图片描述

这是迄今为止未完成的工作

\documentclass[a4paper,10pt]{article}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{matrix,shapes,arrows,positioning,chains}

\begin{document}

% Define block styles
\tikzset{
desicion/.style={
    diamond,
    draw,
    text width=4em,
    text badly centered,
    inner sep=0pt
},
block/.style={
    rectangle,
    draw,
    text width=10em,
    text centered,
    rounded corners
},
cloud/.style={
    draw,
    ellipse,
    minimum height=2em
},
descr/.style={
    fill=white,
    inner sep=2.5pt
},
connector/.style={
    -latex,
    font=\scriptsize
},
rectangle connector/.style={
    connector,
    to path={(\tikztostart) -- ++(#1,0pt) \tikztonodes |- (\tikztotarget) },
    pos=0.5
},
rectangle connector/.default=-2cm,
straight connector/.style={
    connector,
    to path=--(\tikztotarget) \tikztonodes
}
}

\begin{tikzpicture}
\matrix (m)[matrix of nodes, column  sep=2cm,row  sep=8mm, align=center, nodes={rectangle,draw, anchor=center} ]{
    |[block]| {Start}              &  \\
    |[block]| {Assume that $a=c$ the optimilalty cretierin given by }               &                                            \\
    |[desicion]| {Locally optimal}          &                                             \\
   |[block]| {Assume that $a=d$ the optimilalty cretierin given by}    &                                             \\
    |[desicion]| {Locally optimal}         &           |[block]| {Stop}                                   \\
         |[block]| {Assume that $a=e$ the optimilalty cretierin given by}    &    |[desicion]| {Locally optimal}                                          \\
            |[desicion]| {Locally optimal}         &       |[block]| {Assume that $a=k$ the optimilalty cretierin given by}                                      \\
                 |[block]| {Assume that $a=f$ the optimilalty cretierin given by}    &   |[desicion]| {Locally optimal}                                         \\
};
\path [>=latex,->] (m-1-1) edge (m-2-1);
\path [>=latex,->] (m-2-1) edge (m-3-1);
\path [>=latex,->] (m-3-1) edge (m-4-1);
\path [>=latex,->] (m-4-1) edge (m-5-1);
\path [>=latex,->] (m-5-1) edge (m-6-1);
\path [>=latex,->] (m-6-1) edge (m-7-1);
\path [>=latex,->] (m-7-1) edge (m-8-1);
\path [>=latex,->] (m-8-1) edge (m-8-2);
\path [>=latex,->] (m-8-2) edge (m-7-2);
\path [>=latex,->] (m-7-2) edge (m-6-2);
\path [>=latex,->] (m-6-2) edge (m-5-2);

\end{tikzpicture}

\end{document}

在此处输入图片描述

我该如何根据第一张图所示的流程图修复路径?

答案1

尽量foreach使用循环画线,line新增一种样式。

在此处输入图片描述

代码

\documentclass[a4paper,10pt]{article}
\usepackage[margin=1cm]{geometry}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{matrix,shapes,arrows,positioning,chains,calc}

\begin{document}

% Define block styles
\tikzset{
desicion/.style={
    diamond,
    draw, thick,
    text width=4em,
    text badly centered,
    inner sep=0pt
},
block/.style={
    rectangle,
    draw, thick,
    text width=10em,
    text centered,
    rounded corners
},
cloud/.style={
    draw,
    ellipse,
    minimum height=2em
},
descr/.style={
    fill=white,
    inner sep=2.5pt
},
connector/.style={
    -latex,
    font=\scriptsize
},
rectangle connector/.style={
    connector,
    to path={(\tikztostart) -- ++(#1,0pt) \tikztonodes |- (\tikztotarget) },
    pos=0.5
},
rectangle connector/.default=-2cm,
straight connector/.style={
    connector,
    to path=--(\tikztotarget) \tikztonodes
},
line/.style={>=latex,->,thick}
}

\begin{tikzpicture}
\matrix (m)[matrix of nodes, column  sep=3cm,row  sep=8mm, align=center, nodes={rectangle,draw, anchor=center} ]
{
 |[block]| {Start}       &   & \\
 |[block]| {Assume that $a=c$ the optimilalty cretierin given by }  &  &                                  \\
 |[desicion]| {Locally optimal}          &           &                                 \\
 |[block]| {Assume that $a=d$ the optimilalty cretierin given by}    &                                            & \\
 |[desicion]| {Locally optimal}         &               &                           \\
 |[block]| {Assume that $a=e$ the optimilalty cretierin given by}    &       |[block]| {$A=c^2$ \\ $A=b^2$}           &        |[block]| {Globsl \\  Optimal \\ Configuration}                 \\
 |[desicion]| {Locally optimal}         &    &                       \\
 |[block]| {Assume that $a=f$ the optimilalty cretierin given by}    &   &   \\
 |[desicion]| {Locally optimal}               & &  |[block]| {Stop}  \\
 |[block]| {Assume that $a=k$ the optimilalty cretierin given by}    &    |[desicion]| {Locally optimal}    &     \\
};
\foreach \f/\t[evaluate=\f as \t using int(\f+1)]  in {1,2,3,4,5,6,7,8,9}{
\path [line] (m-\f-1) edge (m-\t-1);
}
\path [line,red] (m-10-1) edge (m-10-2);
\draw[line,red] (m-10-2) -- (m-6-2) node[pos=0.3,right,text=black]{ Yes, Pass (a,c)};
\draw [line] (m-6-2) --node[midway,below,text=black]{Yes, Pass (a,c)} node[midway,above,text=black]{Step 6} (m-6-3);
\path [line,red] (m-6-3) edge (m-9-3);
\draw [line,red] (m-10-2) -| (m-9-3);

\foreach \f/\l[evaluate=\f as \t using int(\f+1)] in {3/a,5/b,7/c,9/d}{
\draw [line,red] (m-\f-1.east) --node[midway,above,text=black]{Yes, Pass (a,c)} ++ (2.5cm,0)coordinate[](\l);
\draw [line,red] (m-\f-1.east) -| ([xshift=1.5cm]m-\t-1.north);
}

\node[xshift=-2cm] at (m-3-1){Step 1(4)};
\node[xshift=-2cm] at (m-5-1){Step 2 (7)};
\node[xshift=-2cm] at (m-7-1){Step 3 (9)};
\node[xshift=-2cm] at (m-9-1){Step 4 (3)};
\node[xshift=-2cm,above] at (m-10-2){Step 5};
\draw [>=latex,-,red,thick] (a) --(d);
\draw [line,red] ($(a)!0.5!(d)$) -- (m-6-2);
\end{tikzpicture}

\end{document}

编辑:应 OP 的要求,我在report课堂上进行了案例分析,当然,还提供了 OP 所需的信息。结果如下

在此处输入图片描述

相关代码

\documentclass[a4paper,11pt]{report}
\usepackage[margin=1cm]{geometry}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{matrix,shapes,arrows,positioning,chains,calc}

\begin{document}

% Define block styles
\tikzset{
desicion/.style={
    diamond,
    draw, thick,
    text width=4em,
    text badly centered,
    inner sep=0pt
},
block/.style={
    rectangle,
    draw, thick,
    text width=10em,
    text centered,
    rounded corners
},
cloud/.style={
    draw,
    ellipse,
    minimum height=2em
},
descr/.style={
    fill=white,
    inner sep=2.5pt
},
connector/.style={
    -latex,
    font=\scriptsize
},
rectangle connector/.style={
    connector,
    to path={(\tikztostart) -- ++(#1,0pt) \tikztonodes |- (\tikztotarget) },
    pos=0.5
},
rectangle connector/.default=-2cm,
straight connector/.style={
    connector,
    to path=--(\tikztotarget) \tikztonodes
},
line/.style={>=latex,->,thick}
}

\begin{figure}[!htpb]
\begin{tikzpicture}
\matrix (m)[matrix of nodes, column  sep=3cm,row  sep=8mm, align=center, nodes={rectangle,draw, anchor=center} ]
{
 |[block]| {Start}       &   & \\
 |[block]| {Assume that $a=c$ the optimilalty cretierin given by }  &  &                                  \\
 |[desicion]| {Locally optimal}          &           &                                 \\
 |[block]| {Assume that $a=d$ the optimilalty cretierin given by}    &                                            & \\
 |[desicion]| {Locally optimal}         &               &                           \\
 |[block]| {Assume that $a=e$ the optimilalty cretierin given by}    &       |[block]| {$A=c^2$ \\ $A=b^2$}           &        |[block]| {Globsl \\  Optimal \\ Configuration}                 \\
 |[desicion]| {Locally optimal}         &    &                       \\
 |[block]| {Assume that $a=f$ the optimilalty cretierin given by}    &   &   \\
 |[desicion]| {Locally optimal}               & &  |[block]| {Stop}  \\
 |[block]| {Assume that $a=k$ the optimilalty cretierin given by}    &    |[desicion]| {Locally optimal}    &     \\
};
\foreach \f/\t[evaluate=\f as \t using int(\f+1)]  in {1,2,3,4,5,6,7,8,9}{
\draw [line] (m-\f-1) -- node[midway,right]{No} (m-\t-1);
}
\path [line,red] (m-10-1) edge (m-10-2);
\draw[line,red] (m-10-2) -- (m-6-2) node[pos=0.3,right,text=black]{ Yes, Pass (a,c)};
\draw [line] (m-6-2) --node[midway,below,text=black]{Yes, Pass (a,c)} node[midway,above,text=black]{Step 6} (m-6-3);
\path [line,red] (m-6-3) edge (m-9-3);
\draw [line,red] (m-10-2) -| (m-9-3);

\foreach \f/\l[evaluate=\f as \t using int(\f+1)] in {3/a,5/b,7/c,9/d}{
\draw [line,red] (m-\f-1.east) --node[midway,above,text=black]{Yes, Pass (a,c)} ++ (2.5cm,0)coordinate[](\l);
\draw [line,red] (m-\f-1.east) -| ([xshift=1.5cm]m-\t-1.north);
}
\node[xshift=4cm] at (m-1-1) {A,b,c,d,k given};
\node[xshift=-2cm] at (m-3-1){Step 1(4)};
\node[xshift=-2cm] at (m-5-1){Step 2 (7)};
\node[xshift=-2cm] at (m-7-1){Step 3 (9)};
\node[xshift=-2cm] at (m-9-1){Step 4 (3)};
\node[xshift=-2cm,above] at (m-10-2){Step 5};
\node[above,xshift=1.5cm] at (m-10-2){No};
\draw [>=latex,-,red,thick] (a) --(d);
\draw [line,red] ($(a)!0.5!(d)$) -- (m-6-2);
\end{tikzpicture}
\caption{Your caption here}
\end{figure}
\end{document}

编辑 2:最后,经过几次讨论,就是这样。

在此处输入图片描述

代码

\documentclass[a4paper,11pt]{report}
\usepackage[margin=1cm]{geometry}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{matrix,shapes,arrows,positioning,chains,calc}

\begin{document}

% Define block styles
\tikzset{
desicion/.style={
    diamond,
    draw, thick,
    text width=4em,
    text badly centered,
    inner sep=0pt
},
block/.style={
    rectangle,
    draw, thick,
    text width=9em,
    text centered,
    rounded corners
},
cloud/.style={
    draw,
    ellipse,
    minimum height=2em
},
descr/.style={
    fill=white,
    inner sep=2.5pt
},
connector/.style={
    -latex,
    font=\scriptsize
},
rectangle connector/.style={
    connector,
    to path={(\tikztostart) -- ++(#1,0pt) \tikztonodes |- (\tikztotarget) },
    pos=0.5
},
rectangle connector/.default=-2cm,
straight connector/.style={
    connector,
    to path=--(\tikztotarget) \tikztonodes
},
line/.style={>=latex,->,thick}
}

\begin{figure}[!htpb]
\begin{tikzpicture}
\matrix (m)[matrix of nodes, column  sep=3cm, row  sep=8mm, align=center, nodes={rectangle,draw, anchor=center} ]
{
 |[block]| {Start}       &   & \\
 |[block]| {Assume that $a=c$ the optimilalty cretierin given by }  &  &                                  \\
 |[desicion]| {Locally optimal}          &           &                                 \\
 |[block]| {Assume that $a=d$ the optimilalty cretierin given by}    &                                            & \\
 |[desicion]| {Locally optimal}         &               &                           \\
 |[block]| {Assume that $a=e$ the optimilalty cretierin given by}    &       |[block]| {$A=c^2$ \\ $A=b^2$}           &        |[block]| {Globsl \\  Optimal \\ Configuration}                 \\
 |[desicion]| {Locally optimal}         &    &                       \\
 |[block]| {Assume that $a=f$ the optimilalty cretierin given by}    &   &   \\
 |[desicion]| {Locally optimal}               & &  |[block]| {Stop}  \\
 |[block]| {Assume that $a=k$ the optimilalty cretierin given by}    &    |[desicion]| {Locally optimal}    &     \\
};
\foreach \f/\t[evaluate=\f as \t using int(\f+1)]  in {3,4,5,6,7,8,9}{
\draw [line] (m-\f-1) -- node[midway,right]{No} (m-\t-1);
}
\node[above,xshift=1.5cm] at (m-10-2){No};
\foreach \f/\t[evaluate=\f as \t using int(\f+1)]  in {1,2}{
\draw [line] (m-\f-1) --  (m-\t-1);
}
\path  [line,red] (m-10-1) edge (m-10-2);
\path  [line,red] (m-6-3) edge (m-9-3);
\draw [line,red] (m-10-2) -| (m-9-3);

\draw [line,red] (m-3-1.east) --node[midway,above,text=black]{Yes, Pass (a1,c1)} ++ (2.8cm,0)coordinate[](a);
\draw [line,red] (m-3-1.east) -| ([xshift=1.5cm]m-4-1.north);
\draw [line,red] (m-5-1.east) --node[midway,above,text=black]{Yes, Pass (a2,c2)} ++ (2.8cm,0)coordinate[](b);
\draw [line,red] (m-5-1.east) -| ([xshift=1.5cm]m-6-1.north);
\draw [line,red] (m-7-1.east) --node[midway,above,text=black]{Yes, Pass (a3,c3)} ++ (2.8cm,0)coordinate[](c);
\draw [line,red] (m-7-1.east) -| ([xshift=1.5cm]m-8-1.north);
\draw [line,red] (m-9-1.east) --node[midway,above,text=black]{Yes, Pass (a4,c4)} ++ (2.8cm,0)coordinate[](d);
\draw [line,red] (m-9-1.east) -| ([xshift=1.5cm]m-10-1.north);
\draw[line,red] (m-10-2) -- (m-6-2) node[pos=0.3,right,text=black]{Yes, Pass (a5,c5)};
\draw [line] (m-6-2) --node[midway,below,text=black]{Yes, Pass (a6,c6)} node[midway,above,text=black]{Step 6} (m-6-3);

\node[xshift=4cm] at (m-1-1) {A,b,c,d,k given};
\node[xshift=-2cm] at (m-3-1){Step 1(4)};
\node[xshift=-2cm] at (m-5-1){Step 2 (7)};
\node[xshift=-2cm] at (m-7-1){Step 3 (9)};
\node[xshift=-2cm] at (m-9-1){Step 4 (3)};
\node[xshift=-2cm,above] at (m-10-2){Step 5};
\draw [>=latex,-,red,thick] (a) --(d);
\draw [line,red] ($(a)!0.5!(d)$) -- (m-6-2);
\end{tikzpicture}
\caption{Your caption here}
\end{figure}
\end{document}

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