我已经看到了PGFplots 和表的列中元素数量不同；但这是一个稍微不同的问题……
考虑以下 MWE：
\documentclass{article}
\usepackage{pgfplots}
\usepackage{pgfplotstable}
\usepackage{adjustbox}
\pgfplotstableread[
col sep=comma,
header=false,
% columns/0/.style={string type}, % nowork here; on typeset
]{
c002,128,64,0.000119,-1,-1,0.000162,-1,-1,0.000494,-1,-1,0.001540,1,65,0.001906,0,1,0.002997,1,1,0.003341,0,65,0.004432,1,65,0.004797,0,1,0.005889,1,1,0.006253,0,65,
c003,128,64,0.000166,-1,-1,0.000463,-1,-1,0.001546,1,65,0.001936,0,1,0.002981,1,1,0.003362,0,65,0.004437,1,65,0.004939,0,1,0.005918,1,1,0.006269,0,65,
c004,128,64,0.000118,-1,-1,0.000161,-1,-1,0.000456,-1,-1,0.001518,1,65,0.001903,0,1,0.002973,1,1,0.003339,0,65,0.004410,1,65,0.004795,0,1,0.005866,1,1,0.006252,0,65,
}\mytable
\pgfplotsset{%
compat=1.5.1,
}
\pgfplotstablegetrowsof{\mytable} %Determine no. of rows
\pgfmathtruncatemacro{\rows}{\pgfplotsretval} % pgfmathsetmacro float, this int
\pgfmathtruncatemacro{\lastrow}{\rows-1}
\begin{document}
\typeout{Rows: \rows} % 3.0
Test 1: \\ \newline
\foreach \r in {0,1,...,\lastrow}{
\pgfplotstablegetelem{\r}{[index]0}\of\mytable%
\edef\colzerotag{\pgfplotsretval}%
\pgfplotstablegetcolsof{\mytable} % how to get cols for this row???
\edef\numcolsstr{\pgfplotsretval}%
\noindent \r: \colzerotag\ - \numcolsstr \\
}
% just testing wide printout
\begin{adjustbox}{width=\textwidth}
\noindent\pgfplotstabletypeset[
columns/0/.style={string type},
font=\tiny,
]{\mytable}
\end{adjustbox}
\end{document}
数据的列数可变；我想避免重新解析数据并用空列填充。按原样使用数据pdflatex会失败，并显示以下内容：
% ! 包 pgfplots 错误：输入表 '' 在第 '2' 行的列数不平衡（预期为 '37' 列；实际为 '34'）。输入表可能已损坏？如果您需要不平衡的数据，请考虑在空单元格中使用 'nan'（可能与 'unbounded coords=jump' 结合使用）。
如果你继续按“Enter”，文档最终将被编译，这是输出（单击可查看完整尺寸）：
（呈现了完整的表格，只是为了确认是否像我一样解释每行的数据 - 即“从头开始，并继续执行尽可能多的数据列”；看起来确实如此。附加了一个空列，显然是因为数据中pgfplotstable存在尾随逗号,）
所以，基本上，我想要做的是循环遍历每一行，打印第一列标签作为标识符，然后打印该行的列数；预期输出是：
0: c002 - 37
1: c003 - 37
2: c004 - 34
这里只是作为一个演示，我\pgfplotstablegetcolsof{\mytable}将始终使用表中第一个推导出的列数（因此无论如何它总是打印 37）。
有没有一种方法可以仅使用pgfplotstable（可能使用额外的 Latex 包）来实现这一点，而无需重新解析数据？