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绘制链接树

tag-icon • tag-icon tikz-trees forest
绘制链接树

我有很有帮助先前使用定义树forest（再次感谢 cfr！）。

我希望能够将一棵树分解成子树并在它们之间建立链接……无论是在同一片森林中还是在分离的森林中。

图片将更加容易理解...

从 ：

初始 http://www.weboplanet.com/tests/calculerAire2disques.pdf.png

类似于：

类似的东西http://www.weboplanet.com/tests/calculerAire2disques.pdf_wish.png

我尝试使用“幻影”节点作为根，但子树保持在同一行：

类似的东西http://www.weboplanet.com/tests/calculerAire2disques_wish_resultat.pdf.png

源代码 ：

\documentclass{standalone}
\usepackage[latin1]{inputenc}
\usepackage{forest}
\usetikzlibrary{shapes.geometric}
\begin{document}
\pgfkeys{/forest,
  decision/.append style={diamond, fill=blue!20, text width=5em, inner sep=.5pt, rounded corners},
  io/.append style={trapezium, trapezium left angle=70,trapezium right angle=-70, minimum height=5mm},
  sequence/.append style={fill=red!20, rounded corners},
  nop/.append style={fill=red!5},
  rotor/.append style={inner sep=3pt,outer sep=0,fill opacity=0.3,minimum width=2cm,circle},
  racine/.append style={minimum width=1cm, fill=white!80,circle,
        tikz={
            \draw [circle,draw,line width=0.5pt] ;
            \draw [->,line width=1pt] () ++(160:4mm) arc (-200:40:4mm);}
        }
    }

\begin{forest}for tree={
  child anchor=north,
  parent anchor=south,
  thick,
  draw,
 align=center,
  font=\sffamily\large,
 }
[,phantom
[{Principal\\\hline \mbox{}\\[-1em]reel r1, r2, aire2, PI\\reel aire1, aire\\} 
    [seq, racine
        [initialisation, name=initSrc,sequence
        ] 
        [Traitement, name=trtSrc,sequence
        ] 
        [Resultat, name=resSrc,sequence
        ]
    ]
]
    [initialisation, name=initDest,sequence
        [{ECRIRE "rayon du disque extérieur ?"}, io]
        [{r1$\leftarrow$ LIRE()}, io]
        [{ECRIRE "rayon du disque interieur ?"}, io]
        [{r2$\leftarrow$ LIRE()}, io]
    ] 
    [Traitement, name=trtDest,sequence
        [{aire1$\leftarrow$ PI*r1*r1} ]
        [{aire2$\leftarrow$ PI*r2*r2} ]
        [{aire$\leftarrow$ r1-r2} ]
    ] 
    [Resultat, name=resDest,sequence
        [{ECRIRE "l'aire vaut ",aire}, io]
    ]
]
\draw[->] (initSrc) to[out=north east,in=south] (initDest);
\draw[->] (trtSrc) to[out=north east,in=south] (trtDest);
\draw[->] (resSrc) to[out=north east,in=south] (resDest);
\end{forest}
\end{document}

非常感谢您的帮助 ！

答案1

您可以尝试类似这样的方法。此解决方案使用phantom节点与fit=rectangle和的组合calign with current来排列事物，并确保箭头不会穿过节点和连接线。基本思想是将子树创建为左侧分支的子树，但使用phantom节点来创建，这样它们就不会看就像排版结果中的子树。

\documentclass{standalone}
\usepackage[utf8]{inputenc}
\usepackage{forest}
\usetikzlibrary{shapes.geometric}
\begin{document}
\pgfkeys{/forest,
  decision/.append style={diamond, fill=blue!20, text width=5em, inner sep=.5pt, rounded corners},
  io/.append style={trapezium, trapezium left angle=70,trapezium right angle=-70, minimum height=5mm},
  sequence/.append style={fill=red!20, rounded corners},
  nop/.append style={fill=red!5},
  rotor/.append style={inner sep=3pt,outer sep=0,fill opacity=0.3,minimum width=2cm,circle},
  racine/.append style={minimum width=1cm, fill=white!80,circle,
        tikz={
            \draw [circle,draw,line width=0.5pt] ;
            \draw [->,line width=1pt] () ++(160:4mm) arc (-200:40:4mm);}
        }
    }

\begin{forest}for tree={
  child anchor=north,
  parent anchor=south,
  thick,
  draw,
  align=center,
  font=\sffamily\large,
 }
[{Principal\\\hline \mbox{}\\[-1em]reel r1, r2, aire2, PI\\reel aire1, aire\\}
    [seq, racine
      [initialisation, name=initSrc,sequence, fit=rectangle
        [,phantom
          [initialisation, name=initDest,sequence
              [{ECRIRE "rayon du disque extérieur ?"}, io]
              [{r1$\leftarrow$ LIRE()}, io]
              [,phantom, calign with current
                [,phantom, calign with current
                  [Traitement, name=trtDest,sequence
                      [{aire1$\leftarrow$ PI*r1*r1} ]
                      [{aire2$\leftarrow$ PI*r2*r2}, calign with current
                        [,phantom, calign with current
                          [Resultat, name=resDest,sequence
                              [{ECRIRE "l'aire vaut ",aire}, io]
                          ]
                        ]
                      ]
                      [{aire$\leftarrow$ r1-r2} ]
                  ]
                ]
              ]
              [{ECRIRE "rayon du disque interieur ?"}, io]
              [{r2$\leftarrow$ LIRE()}, io]
            ]
          ]
        ]
        [Traitement, name=trtSrc,sequence
        ]
        [Resultat, name=resSrc,sequence
        ]
      ]
   ]
]
\draw[->] (initSrc) to[out=south east,in=north] (initDest);
\draw[->] (trtSrc) to[out=south east,in=east] (trtDest);
\draw[->] (resSrc) to[out=south east,in=east] (resDest);
\end{forest}
\end{document}

子树和箭头

答案2

根据@cfr 的回答，我将使用'幻影' 节点加法升设置节点垂直位置的选项：

优势：多级节点时容易改变

缺点：跨框链接

编辑：我记住@cfr 的评论：“...森林不是设计用来布局断开的节点的...”，但对我来说，使用下面的解决方案会更容易，直到我可以使用不同分层森林之间的链接。

代码：（仅森林区块，其余不变）

...
\begin{forest}
for tree={
  child anchor=north,
  parent anchor=south,
  thick,
  draw,
  align=center,
  font=\sffamily\large
 }
[,phantom
[{Principal\\\hline \mbox{}\\[-1em]reel r1, r2, aire2, PI\\reel aire1, aire\\} 
    [seq, racine
        [Initialisation , name=initSrc,sequence
        ] 
        [Traitement, name=trtSrc,tier=bottom,sequence
        ] 
        [Resultat, name=resSrc,sequence
        ]]]
[,phantom, l*=6  
        [Initialisation, name=initDest,sequence
            [{ECRIRE "rayon du disque extérieur ?"}, io]
            [{r1$\leftarrow$ LIRE()}, io]
            [{ECRIRE "rayon du disque interieur ?"}, io]
            [{r2$\leftarrow$ LIRE()}, io]
        ]]
[,phantom,l*=9 
        [Traitement, name=trtDest,sequence
            [{aire1$\leftarrow$ PI*r1*r1} ]
            [{aire2$\leftarrow$ PI*r2*r2} ]
            [{aire$\leftarrow$ r1-r2} ]
        ]]
[,phantom, l*=12 
        [Resultat, name=resDest,sequence
            [{ECRIRE "l'aire vaut ",aire}, io]
        ]]
]
\draw[->>,dashed] (initSrc) to[out=south,in=west] (initDest);
\draw[->>,dashed] (trtSrc) to[out=south east,in=east] (trtDest);
\draw[->>,dashed] (resSrc) to[out=south,in=east] (resDest);
\end{forest}
....

图像 ：

解决方案保留 http://www.weboplanet.com/tests/calculerAire2disques_wish.pdf_final.png

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