我正在尝试为以下问题找到一个简单的解决方案。我希望我的定义、命题和证明中的段落之间没有垂直行距，但有一个小的缩进。在这些环境之外，必须没有缩进和正行距。这是当前代码的一个最小示例：
\documentclass{article}
\usepackage{amsthm}
\usepackage{parskip}
\theoremstyle{definition}
\newtheorem{Def}{Definition}[section]
\theoremstyle{remark}
\newtheorem{Exm}{Example}[section]
\theoremstyle{plain}
\newtheorem{Prop}{Proposition}[section]
\setlength{\parskip}{0.3cm plus 0.03cm minus 0.02cm}
\makeatletter
\def\thm@space@setup{%
\thm@preskip=0.5cm plus 0.05cm minus 0.05cm
\thm@postskip=0.2cm plus 0.02cm minus 0.01cm
}
\makeatother
\begingroup
\makeatletter
\@for\theoremstyle:=remark\do{%
\expandafter\g@addto@macro\csname th@\theoremstyle\endcsname{%
\addtolength\thm@preskip\parskip
}%
}
\endgroup
\begin{document}
\section{Example}
\begin{Def}
This is a definition.
With two paragraphs.
\end{Def}
Running text.
\begin{Exm}
And an example.
Again with two paragraphs.
\end{Exm}
More running text.
This time with two paragraphs.
\begin{Prop}
Finally a proposition.
With two paragraphs.
\end{Prop}
\begin{proof}
Notice that it is clear.
And therefore it is so.
\end{proof}
\end{document}
然而我想要的是看起来像以下结果的东西，但这是自动完成的：
\documentclass{article}
\usepackage{amsthm}
\usepackage{parskip}
\theoremstyle{definition}
\newtheorem{Def}{Definition}[section]
\theoremstyle{remark}
\newtheorem{Exm}{Example}[section]
\theoremstyle{plain}
\newtheorem{Prop}{Proposition}[section]
\setlength{\parskip}{0.3cm plus 0.03cm minus 0.02cm}
\makeatletter
\def\thm@space@setup{%
\thm@preskip=0.5cm plus 0.05cm minus 0.05cm
\thm@postskip=0.2cm plus 0.02cm minus 0.01cm
}
\makeatother
\begingroup
\makeatletter
\@for\theoremstyle:=remark\do{%
\expandafter\g@addto@macro\csname th@\theoremstyle\endcsname{%
\addtolength\thm@preskip\parskip
}%
}
\endgroup
\newcommand{\tab}{\hspace*{2em}}
\begin{document}
\section{Example}
\begin{Def}
This is a definition.
\\
\tab With two paragraphs.
\end{Def}
Running text.
\begin{Exm}
And an example.
\\
\tab
Again with two paragraphs.
\end{Exm}
More running text.
This time with two paragraphs.
\begin{Prop}
Finally a proposition.
\\
\tab
With two paragraphs.
\end{Prop}
\begin{proof}
Notice that it is clear.
\\
\tab
And therefore it is so.
\end{proof}
\end{document}
我还没有找到任何解决方案。任何帮助我都感激不尽。
答案1
我最终使用了类似下面的方法。解决方案比我预期的要简单，而且结果也很好。
\documentclass{article}
\usepackage{amsthm}
\usepackage{parskip}
\theoremstyle{definition}
\newtheorem{Def}{Definition}[section]
\theoremstyle{remark}
\newtheorem{Exm}{Example}[section]
\theoremstyle{plain}
\newtheorem{Prop}{Proposition}[section]
\setlength{\parskip}{0cm}
\setlength{\parindent}{0.5cm}
\setlength{\topsep}{0.35cm plus 0.2cm minus 0.2cm}
\makeatletter
\def\thm@space@setup{%
\thm@preskip=0.45cm plus 0.3cm minus 0.16cm
\thm@postskip=0.25cm plus 0.05cm minus 0.16cm
}
\makeatother
\begin{document}
...
\end{document}