以可变高度垂直分隔页面

Question 1

如果我明白你的问题了，这个可能，可能做一些模糊的你想要的事情。但我对此非常没有信心！

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{calc}
\usepackage{blindtext}
\newlength{\mytopheight}
\newlength{\mybotheight}
\newcommand*\mymidrule{\noindent\rule[1mm]{\linewidth}{2pt}}
\newlength{\targetheight}
\setlength{\targetheight}{\dimexpr\textheight-2pt-2\baselineskip-2\parskip}% if an adjustment is needed for the rule width
\newlength{\lengtha}
\newsavebox{\mytop}
\newsavebox{\mybot}
\newlength{\normalparindent}
\setlength{\normalparindent}{\parindent}
\newcommand\myrulesplit[2]{%
  \sbox{\mytop}{%
    \begin{minipage}[t]{\linewidth}
      \setlength{\parindent}{\normalparindent}%
        #1
    \end{minipage}%
  }%
  \sbox{\mybot}{%
    \begin{minipage}[t]{\linewidth}
      \setlength{\parindent}{\normalparindent}%
        #2
    \end{minipage}%
  }%
  \settototalheight{\mytopheight}{\usebox{\mytop}}%
  \ifdim\mytopheight>.5\targetheight#1\par\mymidrule\par#2
  \else
    \settototalheight{\mybotheight}{\usebox{\mybot}}%
    \ifdim\mybotheight>.5\targetheight
      \setlength{\lengtha}{\dimexpr\mytopheight+\mybotheight}%
      \ifdim\lengtha>\targetheight#1\par\mymidrule\par#2
      \else#1\vfill\par\mymidrule\par#2%
      \fi
    \else
      \smash{\usebox{\mytop}}\vfill\par\mymidrule\par\smash{\usebox{\mybot}}\vfill%
    \fi
  \fi
}

\begin{document}
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext

    \blindtext
  }
  \clearpage
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext

    \blindtext

    \blindtext

    \blindtext
  }
  \clearpage
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext
  }
\end{document}

3 种场景

Answer

如果我明白你的问题了，这个可能，可能做一些模糊的你想要的事情。但我对此非常没有信心！

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{calc}
\usepackage{blindtext}
\newlength{\mytopheight}
\newlength{\mybotheight}
\newcommand*\mymidrule{\noindent\rule[1mm]{\linewidth}{2pt}}
\newlength{\targetheight}
\setlength{\targetheight}{\dimexpr\textheight-2pt-2\baselineskip-2\parskip}% if an adjustment is needed for the rule width
\newlength{\lengtha}
\newsavebox{\mytop}
\newsavebox{\mybot}
\newlength{\normalparindent}
\setlength{\normalparindent}{\parindent}
\newcommand\myrulesplit[2]{%
  \sbox{\mytop}{%
    \begin{minipage}[t]{\linewidth}
      \setlength{\parindent}{\normalparindent}%
        #1
    \end{minipage}%
  }%
  \sbox{\mybot}{%
    \begin{minipage}[t]{\linewidth}
      \setlength{\parindent}{\normalparindent}%
        #2
    \end{minipage}%
  }%
  \settototalheight{\mytopheight}{\usebox{\mytop}}%
  \ifdim\mytopheight>.5\targetheight#1\par\mymidrule\par#2
  \else
    \settototalheight{\mybotheight}{\usebox{\mybot}}%
    \ifdim\mybotheight>.5\targetheight
      \setlength{\lengtha}{\dimexpr\mytopheight+\mybotheight}%
      \ifdim\lengtha>\targetheight#1\par\mymidrule\par#2
      \else#1\vfill\par\mymidrule\par#2%
      \fi
    \else
      \smash{\usebox{\mytop}}\vfill\par\mymidrule\par\smash{\usebox{\mybot}}\vfill%
    \fi
  \fi
}

\begin{document}
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext

    \blindtext
  }
  \clearpage
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext

    \blindtext

    \blindtext

    \blindtext
  }
  \clearpage
  \myrulesplit{%
    \begin{longtabu}{XXX} %#1
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
      1 & 2 & 3 \\
      4 & 5 & 6 \\
      7 & 8 & 9 \\
    \end{longtabu}
  }{%
    \blindtext
  }
\end{document}

3 种场景

Question 2

这是其中一种方法。它\raisebox正好占据了半页。

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{blindtext}

\newsavebox{\tempbox}

\begin{document}
\noindent\raisebox{-\height}[0pt][0.5\textheight]{%
\begin{minipage}{\textwidth}
\begin{longtabu}{XXX} %#1
  1 & 2 & 3 \\
  4 & 5 & 6 \\
  7 & 8 & 9 \\
\end{longtabu}
\end{minipage}}
\noindent\rule[1mm]{1.0\textwidth}{2pt} %#2
\blindtext %#3

\end{document}

这是另一个。由于每个都\vfill扩展到相同的大小，因此上方和下方占用的空间必须相同。 \smash使它们实际上不占用任何空间。可以使用\rlap和\llap在水平方向上实现相同的效果。

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{blindtext}

\newsavebox{\tempbox}

\begin{document}
\noindent\smash{\begin{minipage}[t]{\textwidth}
\begin{longtabu}{XXX} %#1
  1 & 2 & 3 \\
  4 & 5 & 6 \\
  7 & 8 & 9 \\
\end{longtabu}
\end{minipage}}
\vfill
\noindent\rule[1mm]{1.0\textwidth}{2pt} %#2
\noindent\smash{\begin{minipage}[t]{\textwidth}
\blindtext %#3
\end{minipage}}
\vfill
\end{document}

Answer

这是其中一种方法。它\raisebox正好占据了半页。

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{blindtext}

\newsavebox{\tempbox}

\begin{document}
\noindent\raisebox{-\height}[0pt][0.5\textheight]{%
\begin{minipage}{\textwidth}
\begin{longtabu}{XXX} %#1
  1 & 2 & 3 \\
  4 & 5 & 6 \\
  7 & 8 & 9 \\
\end{longtabu}
\end{minipage}}
\noindent\rule[1mm]{1.0\textwidth}{2pt} %#2
\blindtext %#3

\end{document}

这是另一个。由于每个都\vfill扩展到相同的大小，因此上方和下方占用的空间必须相同。 \smash使它们实际上不占用任何空间。可以使用\rlap和\llap在水平方向上实现相同的效果。

\documentclass{scrartcl}
\usepackage{longtable}
\usepackage{tabu}
\usepackage{blindtext}

\newsavebox{\tempbox}

\begin{document}
\noindent\smash{\begin{minipage}[t]{\textwidth}
\begin{longtabu}{XXX} %#1
  1 & 2 & 3 \\
  4 & 5 & 6 \\
  7 & 8 & 9 \\
\end{longtabu}
\end{minipage}}
\vfill
\noindent\rule[1mm]{1.0\textwidth}{2pt} %#2
\noindent\smash{\begin{minipage}[t]{\textwidth}
\blindtext %#3
\end{minipage}}
\vfill
\end{document}

以可变高度垂直分隔页面

答案1

答案2

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