\documentclass{article}
\def\ad#1{$^{#1}$}
\def\aff#1{$^{#1}$}
\def\address#1{#1}
\def\dept#1{#1}
\def\inst#1{#1}
\def\cyname#1{#1}
\def\country#1{#1}
\def\pcode#1{#1}
\def\stname#1{#1}
\def\phone#1{#1}
\def\fax#1{#1}
\def\ad#1{$^{\rm #1}$}
\def\aff#1{$^{#1}$}
\def\fn#1{#1}
\def\sn#1{#1}
\def\corr#1{#1}
\def\statename#1{#1}
\begin{document}
\title{Sample}
\author{Sas Santhome\ad{a} Author\ad{b} and Susanna Waxxarin\ad{c} }
\maketitle
\address{\aff{a}\dept{Department of Sciences}, \inst{University}, \cyname{City}, \country{Italy}; \aff{b}\dept{Department of Economics}, \inst{University}, \cyname{Trieste}, \country{Italy}}
\end{document}
我想要实现的是\author我有\ad{}'n'次，
链接文本\ad{a}也应该在那里\aff{a}，否则我需要显示编译错误，
例如在上面的代码中，我们可以看到
\ad{a} - \aff{a}
\ad{b} - \aff{b}
\ad{c} - Missing \aff{c}
\aff{c} 缺失，但 \ad{c} 存在，因此我应该抛出编译错误
请指导
答案1
例如，您可以将\ad标签保存到宏中，并在需要时\afflist使用这些标签。这意味着您不需要再次重复标签，并且宏的使用无需参数。\afflist\aff\aff
\def\addto#1#2{\expandafter\def\expandafter#1\expandafter{#1#2}}
\def\ad#1{$^{\rm #1}$\global\addto\afflist{{#1}}}
\def\aff{%
\ifx\afflist\empty \errmessage{There is more \noexpand\aff than \string\ad}%
\else \expandafter\affA\afflist\end $^{\rm\tmp}$%
\fi
}
\def\affA#1#2\end{\gdef\afflist{#2}\def\tmp{#1}}
\def\address#1{#1%
\ifx\afflist\empty\else \errmessage{There is more \noexpand\ad than \string\aff}\fi
}
\def\afflist{}
\def\dept#1{#1}
\def\inst#1{#1}
\def\cyname#1{#1}
\def\country#1{#1}
\def\pcode#1{#1}
\def\stname#1{#1}
\def\phone#1{#1}
\def\fax#1{#1}
\def\fn#1{#1}
\def\sn#1{#1}
\def\corr#1{#1}
\def\statename#1{#1}
...
\address{\aff\dept{Department of Sciences}, \inst{University}, \cyname{City}, \country{Italy};
\aff\dept{Department of Economics}, \inst{University}, \cyname{Trieste}, \country{Italy};
\aff\dept{Somewhere}}
如果需要\aff再次重复宏中的标签，那么您可以检查标签是否相同：
\def\aff#1{\def\tmpa{#1}%
\ifx\afflist\empty \errmessage{There is more \noexpand\aff than \string\ad}%
\else \expandafter\affA\afflist\end $^{\rm\tmp}$%
\ifx\tmp\tmpa \else \errmessage{unmatched labels \tmpa--\tmp}\fi
\fi
}